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sukhopar [10]
3 years ago
14

Which is bigger 80%of 90 or 1/2 of 140

Mathematics
1 answer:
lyudmila [28]3 years ago
4 0

Answer:80% of 90 is bigger


Step-by-step explanation:

80% of 90


N= 90/100×80

N= 90/100× 80/100

N=7200/100

N=72


So 80% of 90 is 72


1/2 of 140

70+70=140

So half of 140 is 70.

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mars1129 [50]

Answer:

1.\:2^x=64, x=\boxed{6},\\2.\:x=\left(\frac{2}{3}\right)^3,x=\boxed{\frac{8}{125}}\\3.\:3\cdot (3^4)=3^x, x=\boxed{5}\\4.\:\frac{16}{25}=x^2,x=\boxed{\frac{4}{5}},

Step-by-step explanation:

1.\\\\2^x=64,\\\log 2^x=\log64,\\x\log 2=\log 64,\\x=\frac{\log 64}{\log 2}=\boxed{6}

2.\\x=\left(\frac{2}{5}\right)^3=\frac{2^3}{5^3}=\boxed{\frac{8}{125}}

3. This problem incorporates an exponent property.

Exponent property used: a^b\cdot a^c=a^{(b+c)}, yielding an answer of \boxed{5}

4.\\\\\frac{16}{25}=x^2,\\x=\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\boxed{\frac{4}{5}}

3 0
3 years ago
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In the diagram the length of segment TR can be represented by 5x-4.
masya89 [10]

Answer: The correct option is D, i.e., 15 units.

Explanation:

It is given that the  length of segment TR can be represented by 5x-4.

From figure it is noticed that the side TR and RV is equal and the length of segment RV is 2x+5. So,

5x-4=2x+5

3x=9

x=3

The value of x is 3, so the length of side RV is,

2x+5=2(3)+5=11

In triangle TRS and angle VRS,

TR=VR

\angle TRS=\angle VRS=90^{\circ}

RS=RS (common side)

By SAS rule of congruence triangle,

\triangle TRS\cong\triangle VRS

Therefore the side TS and VS are congruent sides.

From figure it is noticed that the length of side TS is 6x-3, therefore the length of side VS is also 6x-3.

VS=6x-3=6(3)-3=15

Hence, the length of side VS is 15 units and option D is correct.

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4 years ago
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JulsSmile [24]

Answer:

answer is F. 5

Step-by-step explanation:

5 is the answer

4 0
3 years ago
(0,0) (-4,-4) (2,-4) graph the image of this triangle after a dilation with a scale factor of 2 centered at the origin​
Amiraneli [1.4K]

Answer:

The image coordinates are:

A'(0, 0)

B'(-8, -8)

C'(4, -8)

The graph of the image coordinates attached below.

The image triangle A'B'C' is illustrated in green color.

Step-by-step explanation:

Let the points of a triangle be

  • A(0,0)
  • B(-4,-4)
  • C(2,-4)

We need to determine the graph of the image of this triangle after a dilation with a scale factor of 2 centered at the origin.

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A dilation by a scale factor of 2 centered at the origin means the coordinates of the image can be obtained by multiplying the original coordinates with 2.

Next, the rule of dilation by a scale factor of 2 is given by

Dilation: (x, y)  →  (2x, 2y), centered at (0, 0)

P(x, y)  → P' (2x, 2y)

A(0, 0) → A' (2(0), 2(0)) → A'(0, 0)

B(-4, -4) → B' (2(-4), 2(-4)) → B'(-8, -8)

C(2,-4) → C' (2(2), 2(-4)) → C'(4, -8)

Therefore, the image coordinates are:

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  • C'(4, -8)

The graph of the image coordinates attached below.

The image triangle A'B'C' is illustrated in green color.

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Answer:

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Step-by-step explanation:

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