The top one, hope this is right :)
Answer: (x+4) (x+2)
Step-by-step explanation:
x^2 + 2x + 4x +8
Answer:
12 seconds.
Step-by-step explanation:
If you put it like 15/9 = 20/x, then cross multiply and divide you do 9 times 20 you get 180, then you divide 180 by 15 and you get 12. Hope this helps!
Dimensions are length 20 meter and width 14 meter
<em><u>Solution:</u></em>
Let "a" be the length of rectangle
Let "b" be the width of rectangle
Given that,
<em><u>A rectangle has width that is 6 meters less than the length</u></em>
Width = length - 6
b = a - 6
The area of the rectangle is 280 square meters
<em><u>The area of the rectangle is given by formula:</u></em>
![Area = length \times width](https://tex.z-dn.net/?f=Area%20%3D%20length%20%5Ctimes%20width)
<em><u>Substituting the values we get,</u></em>
![Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0](https://tex.z-dn.net/?f=Area%20%3D%20a%20%5Ctimes%20%28a-6%29%5C%5C%5C%5C280%20%3D%20a%5E2-6a%5C%5C%5C%5Ca%5E2-6a%20-280%3D0)
<em><u>Solve the above equation by quadratic formula</u></em>
![\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3Aa%5C%3Aquadratic%5C%3Aequation%5C%3Aof%5C%3Athe%5C%3Aform%5C%3A%7Dax%5E2%2Bbx%2Bc%3D0%5Cmathrm%7B%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7D%5C%5C%5C%5C%5Cquad%20x_%7B1%2C%5C%3A2%7D%3D%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7D%5Cquad%20a%3D1%2C%5C%3Ab%3D-6%2C%5C%3Ac%3D-280%3A%5Cquad%20a_%7B1%2C%5C%3A2%7D%3D%5Cfrac%7B-%5Cleft%28-6%5Cright%29%5Cpm%20%5Csqrt%7B%5Cleft%28-6%5Cright%29%5E2-4%5Ccdot%20%5C%3A1%5Cleft%28-280%5Cright%29%7D%7D%7B2%5Ccdot%20%5C%3A1%7D)
![a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14](https://tex.z-dn.net/?f=a%20%3D%5Cfrac%7B6%20%5Cpm%20%5Csqrt%7B36%2B1120%7D%7D%7B2%7D%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B6%20%5Cpm%20%5Csqrt%7B1156%7D%7D%7B2%7D%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B6%20%5Cpm%2034%7D%7B2%7D%5C%5C%5C%5CThus%5C%20we%5C%20have%5C%20two%5C%20solutions%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B6%2B34%7D%7B2%7D%20%5Ctext%7B%20or%20%7D%20a%20%3D%20%5Cfrac%7B6-34%7D%7B2%7D%5C%5C%5C%5Ca%20%3D%2020%20%5Ctext%7B%20or%20%7D%20a%20%3D%20-14)
Since, length cannot be negative, ignore a = -14
<em><u>Thus solution of length is a = 20</u></em>
Therefore,
width = length - 6
width = 20 - 6 = 14
Thus dimensions are length 20 meter and width 14 meter
Answer :
i what explanation can u post the picture