Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃
We must first convert from a word equation to a symbol equation:to a symbol equation:
Lead (II) Nitrate + Potassium Iodide → Lead (II) Iodide + Potassium Nitrate
The lead (II) ion is represented as Pb²⁺ , whilst the nitrate ion is NO⁻₃
To balance the charges, we require two nitrate ions per lead (II) ion, and so lead (II) nitrate is Pb(NO₃)₂
The potassium ion is K ⁺ and the iodide ion is I ⁻
The two charges balance in 1:1 ratio, giving a formula of KNO₃
The symbol equation is as follows:
Pb(NO₃)₂ + KI →PbI₂ + KNO ₃
The most obvious change we must make, when balancing this equation, is to increase the number of nitrate ions on the right hand side of the equation. We can to this by placing a coefficient of 2 before the potassium nitrate:
Pb(NO₃)₂ +KI →PbI₂ +2KNO₃
In doing this we have upset the balance of potassium ions on each side of the equation.
Again, we can fix this: we must simply place another coefficient of 2, this time before the potassium iodide:
Pb(NO₃)₂ +2KI → PbI₂ +2KNO ₃
Concluding :
Checking over the equations once more, you will notice that we initially had 1 iodide ion on the right hand side, but 2 on the left. However, we already dealt with this in balancing out potassium ions. Now, our equation is balanced.
And that's it! One last thing to add is that you may have noticed the irregularity in iodide ions rather than nitrate ions. In this case, you would arrived at the same answer simply by working backwards.
Learn more about balanced equation :
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