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3 years ago

Which method preserves an image of a leaf?.

Chemistry

2 answers:

Masteriza [31]3 years ago

6 0

Answer:

As the leaf decomposes, the carbon of the leaf is left in the rock.

Explanation:

A fossil is any rest of the organism or its activity that has a minimum age of 10 thousand years. That is, fossils are the remains or marks of extinct animals, which after death their bodies or marks of their activity have been preserved in some way.

After the death of animals and plants, their components are recycled to be part of other beings, thus completing a cycle of life. For an organism to fossilize, special processes must occur that allow its preservation. When this type of situation occurs, then fossilization occurs.

Then, fossilization is the set of processes that make an organism, some of its parts or traces of its activity, become part of the fossil record.

When vegetables are printed in the sediment leaving their mark, as in this case where an image of a leaf is preserved, it is called "Impressions and Compressions." Then the tissue of the leaf degrades, leaving a trace of where the leaf once was. Finally, as the leaf decomposes, the carbon of the leaf is left in the rock.

Sav [38]3 years ago

5 0

Answer:

Tree sap flows over the leaf and preserves it.

Explanation:

Amber would preserve the image.

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A gas at 928 kpa, 129 C occupies a volume of 569 L. Calculate the volume at 319 kpa and 32 C.

lisabon 2012 [21]

Answer:

1255.4L

Explanation:

Given parameters:

P₁ = 928kpa

T₁ = 129°C

V₁ = 569L

P₂ = 319kpa

T₂ = 32°C

Unknown:

V₂ = ?

Solution:

The combined gas law application to this problem can help us solve it. It is mathematically expressed as;

$\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }$

P, V and T are pressure, volume and temperature

where 1 and 2 are initial and final states.

Now,

take the units to the appropriate ones;

kpa to atm, °C to K

P₂ = 319kpa in atm gives 3.15atm

P₁ = 928kpa gives 9.16atm

T₂ = 32°C gives 273 + 32 = 305K

T₁ = 129°C gives 129 + 273 = 402K

Input the values in the equation and solve for V₂;

$\frac{9.16 x 569}{402} = \frac{3.15 x V_{2} }{305}$

V₂ = 1255.4L

4 0

3 years ago

Consider the chemical equation below. Upper M g (upper O upper H) subscript 2 plus 2 upper H upper N upper O subscript 3 right a

masha68 [24]

Answer:

Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O.

Explanation:

i just took the test , i hope this helps:)

8 0

3 years ago

Read 2 more answers

What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The

Effectus [21]

Answer: The energy released in the given nuclear reaction is 1.3106 MeV.

Explanation:

For the given nuclear reaction:

$_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}$

We are given:

Mass of $_{19}^{40}\textrm{K}$ = 39.963998 u

Mass of $_{20}^{40}\textrm{Ca}$ = 39.962591 u

To calculate the mass defect, we use the equation:

$\Delta m=\text{Mass of reactants}-\text{Mass of products}$

Putting values in above equation, we get:

$\Delta m=(39.963998-39.962591)=0.001407u$

To calculate the energy released, we use the equation:

$E=\Delta mc^2\\E=(0.001407u)\times c^2$

$E=(0.001407u)\times (931.5MeV)$ (Conversion factor: $1u=931.5MeV/c^2$ )

$E=1.3106MeV$

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0

3 years ago

What is the boiling point of water at an elevation of 1.55×104 ft ?

horsena [70]

The computation for this problem is:
(1.55x10^4 / 1.0x10^3) x 19.8 mm Hg
= 15.5 x 19.88 mm Hg
= 308.14 mm Hg decrease
= 308.14 x 0.05 C = 15.407 deg C
deduct this amount to 100
100 – 15.407 = 84.593 C
ANSWER: 85 deg C (rounded to 2 significant figures)

4 0

3 years ago

Help ASAP PLEASE !!!!!!

expeople1 [14]

The answer would be B. Increased fertility downstream. Hope this helps. It's been a while since iv'e done the test, but I think this is the correct answer.

4 0

3 years ago