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3 years ago

Which answer choice best describes the difference between folded mountains and fault-block mountains?

Chemistry

2 answers:

melamori03 [73]3 years ago

6 0

The answer is; C

In folding, when segments of Earth's crust are bent and doubled over, the sediments in between are form folds, since they are forced into a smaller space. This also occurs in converging plates boundaries.

Block Mountains occur when stress due to compression in the crust causes the hanging wall between a fault to move up relative to the footwall.

solong [7]3 years ago

4 0

Answer:

The answer is; C

Block Mountains occur when stress due to compression in the crust causes the hanging wall between a fault to move up relative to the footwall.

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Which of the following feedbacks can be either positive or negative?

miv72 [106K]

Answer:

Cloud cover feedback

Explanation:

6 0

2 years ago

34 atoms of carbon (C) react with 22 molecules of hydrogen gas (H2). How many molecules of methane (CH4) will be formed, and wha

kolbaska11 [484]

Answer:

11 molecules of CH4.

23 atoms of C is the leftover.

Explanation:

Hello!

In this case, for the formation of methane:

$C+2H_2\rightarrow CH_4$

We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:

$molecules _{H_2}=34atomC*\frac{2molec\ H_2}{1atomC} =68molec\ H_2$

Thus, the formed molecules of methane are computed below:

$molec\ CH_4=22molec\ H_2 *\frac{1molec\ CH_4}{2molmolec\ H_2} \\\\molec\ CH_4=11molec\ CH_4$

In such a way, the leftover of carbon atoms are:

$atoms \ C^{left over}=34-22molec\ H_2*\frac{1atoms C}{2molec\ H_2} \\\\atoms \ C^{left over}=23 atoms C$

Best regards!

4 0

2 years ago

A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and

Romashka [77]

Answer: The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C

Explanation:

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute $(S_8)$ = 0.800 g

$M_{solute}$ = Molar mass of solute $(S-8)$ = 256.52 g/mol

$W_{solvent}$ = Mass of solvent (acetic acid) = 100.0 g

Putting values in above equation, we get:

$\text{Molality of solution}=\frac{0.800\times 1000}{256.52\times 100.0}\\\\\text{Molality of solution}=0.0312m$

Calculation for freezing point of solution:

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

$\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

or,

$\text{Freezing point of acetic acid}-\text{Freezing point of solution}=iK_fm$

where,

Freezing point of acetic acid = 16.6°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal freezing point depression constant = 3.59°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$16.6^oC-\text{freezing point of solution}=1\times 3.59^oC/m\times 0.0312m\\\\\text{Freezing point of solution}=16.5^oC$

Hence, the freezing point of solution is 16.5°C

Calculation for boiling point of solution:

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of acetic acid}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

or,

$\text{Boiling point of solution}-\text{Boiling point of acetic acid}=iK_fm$

where,

Boiling point of acetic acid = 118.1°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal boiling point elevation constant = 3.08°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$\text{Boiling point of solution}-118.1^oC=1\times 3.08^oC/m\times 0.0312m\\\\\text{Boiling point of solution}=118.2^oC$

Hence, the boiling point of solution is 118.2°C

8 0

3 years ago

What was a major accomplishment of the Apollo mission

denpristay [2]

Hi there!

The major accomplishment of the Apollo missions was to successfully land Americans on the Moon and to return them safely to Earth. One major reason for this was to establish a way for us to travel to other celestial bodies safely so we could research them and study how they work or to see if they are inhabitable.

-Your friend, ASIAX

4 0

3 years ago

Which physical method can be used for obtaining a sample of salt from a sm

lana [24]

The physical method that can be used for obtaining a sample of salt from a small beaker of salt and water would be evaporation.

<h3>Separation of salt and water</h3>

A mixture of salt and water can be separated by a method known as evaporation. This is based on the assumption that the salt in question is a water-soluble salt.

In order to separate the salt/water mixture:

Place the mixture in a suitable evaporating dish
Boil the mixture until all the water evaporates.
The remaining residue would be the salt

Care should be taken not to overheat the residue in order to avoid melting. Evaporation is generally used to separate a mixture of water and soluble salt. If the salt is insoluble, filtration using a suitable filter paper will filter off the salt while the water is collected as the filtrate.

More on evaporation can be found here: brainly.com/question/1097783

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Which physical method can be used for obtaining a sample of salt from a small beaker of salt water?

6 0

1 year ago