Answer:
A = 57°
B = 19°
C = 104°
Step-by-step explanation:
We have a triangle with 3 angles:
A, B, and C.
We know that:
"Angle A is 3 times larger than angle B"
We can write this as:
A = 3*B
"Angle C was 10° less than 6 times angle B"
This can be written as:
C = 6*B - 10°
And we also know that the sum of all interior angles of a triangle is 180°
Then we also have the equation:
A + B + C = 180°
So we have a system of 3 equations:
A = 3*B
C = 6*B - 10°
A + B + C = 180°
To solve this, the first step is to isolate one of the variables in one of the equations.
We can see that A is already isolated in the first one, so we can skip that step.
Now we need to replace A in the other equations, to get:
C = 6*B - 10°
(3*B) + B + C = 180°
Now we have a system of two equations.
Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:
3*B + B + (6*B - 10°) = 180°
Now we can solve this for angle B
4*B + 6*B - 10° = 180°
10*B - 10° = 180°
10*B = 180° + 10° = 190°
B = 190°/10 = 19°
Now that we know the measure of angle B, we can input this in the equations:
A = 3*B
C = 6*B - 10°
To find the measures of the other two angles:
A = 3*19° = 57°
C = 6*19° - 10° = 104°
Answer: the answer is 6.38
Step-by-step explanation: You have to divide 25.40/4 you can use base ten blocks or draw it out or just divide that is how i got the answer!
Answer:
Step-by-step explanation:
let 7 + 3√2 be an rational number where
7+3√2 = a/b [ a and b are coprime and b is not equal to zero]
3√2= a/b-7
3√2 =( a-7b) /b
√2 = (a-7b) /3b .....(i)
Now ,from equation (i) ,we get that √2 is rational but we know that √2 is irrational. so actually 7 + 3√2 is irrational not rational. thus our assumption is wrong. The number is irrational.
Separate them first.
7+8=15
5/6+2/6=7/6
There can't be 7/6, so it becomes 1 and 1/6,
15+1+1/6=16 1/6
The answer is 16 1/6.
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