If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Answer:
1. Not equal
2. Equal but not connected
3. Equal
4. Equal
Step-by-step explanation: Sorry if not correct :(
Hello,
<span>SA = s^2 + 2 × s × l
Base = 4
SA= 4^2 + 2 x 4 x l
SA= 16 + 2 x 4 x l
SA= 16 + 8 x l
Simplified, the surface area of a square pyramid with a base of 4 and an </span>unknown length/height (l) is SA= 16 + 8 x l.
Faith xoxo
Answer:
1. vertical-line test
2.y=x
3.x
4.domain
Step-by-step explanation:
I just did it on edg and it’s right.
