All categories

4 years ago

Please help! Fraction Problem! :0!! will rate! 15 points!

Mathematics

1 answer:

Fantom [35]4 years ago

3 0

Combine the constant terms, separately from the rest, and then combine the "v" terms, separately from the rest:

-6/5 + 4/15 - (2/3)v + (1/3)v

The LCD of the first 2 terms is 15, so we have -18/15 + 4/15, or -14/15.

The LCD of the last 2 terms is also 15, so we have -(10/15)v + (5/15)v, or (-5/15)v.

The final result is (1/15)(-14 - 5v), or

14+5v

- -------------

You might be interested in

In a simple random sample of 14001400 young people, 9090% had earned a high school diploma. Complete parts a through d below.

ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has increased.

Step-by-step explanation:

Let p = proportion of young people who had earned a high school diploma.

A sample of n = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

$\hat p=0.90$

(a)

The standard error for the estimate of the percentage of all young people who earned a high school diploma is given by:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Compute the standard error value as follows:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=\sqrt{\frac{0.90(1-0.90)}{1400}}\\$

$=0.008$

Thus, the standard error for the estimate of the percentage of all young people who earned a high school diploma is 0.0080.

(b)

The margin of error for (1 - α)% confidence interval for population proportion is:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

Compute the critical value of z for 95% confidence level as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

$=1.96\times 0.0080\\=0.01568\\\approx1.6\%$

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

$CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)$

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has increased, the hypothesis is defined as:

H₀: The percentage of young people who earn high school diplomas has not increased, i.e. p = 0.80.

Hₐ: The percentage of young people who earn high school diplomas has not increased, i.e. p > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of p, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has increased.

8 0

3 years ago

Tasha lists all the multiple of 3 from 3 to99. Tony lists all the multiples of 5 from 5 to100. What is the first number that is

IrinaVladis [17]

Answer:

Multiples of 3 = 3, 9
Multiples of 5 = 5, 10

Step-by-step explanation:

In a list of 3 to 99, the first multiple of 3 will be none other than 3 itself because when multiplied by 1, you get three.

The second number will be: 3 * 2 = 6

In a list from 5 to 100, the first multiple will be 5 with 5 being a multiple of itself when multiplied by 1.

Second number = 5 * 2 = 10

7 0

3 years ago

Keanu and Jeremy sold 25 boxes of popcorn for fundraiser Tiana so 60% of the boxes how many boxes did each cell

Simora [160]

Answer:

Tiana sold 15 boxes and Jeremy and Keanu sold 10

Step-by-step explanation:

60% of 25 = 15

25 - 15 is 10

This is the way I understand the problem.

7 0

3 years ago

Answer pleaseee not 120

hjlf

Answer:

x=82

Step-by-step explanation:

53+45=98

180-98=82

8 0

3 years ago

Addison earn $25 mowing her neighbor's lawn then she loaned her friend $18 and got 50 from her grandmother for her birthday she

yarga [219]

Solution: The total money did addison have to begin with is $29.

Explanation:

Let the addison begin with money $x.

It is given that the addison earn $25 from his neighbor and $50 from her grandmother. So total money addison has $\$x+\$25+\$50=\$x+\$75$

She loaned her friend %18.

Now she has $\$x+\$75-\$18=\$x+\$57$

It is given that she had $86.

$\$x+\$57=\$86\\\$x=\$86-\$57\\\$x=\$29$

Therefore, the total money did addison have to begin with is $29.

4 0

4 years ago

Read 2 more answers