If by that you mean
24x^3 and 14x^2 × y^2,
The Gcf between them is
2x^2
Proof: 24x^3/2x^2 = 12x
(14x^2 × y^2)/2x^2 = 7y^2
since there is no common factor between 12x and 7y^2, 2x^2 is the greates common factor
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.
Step-by-step explanation:
Area is 2D, and Volume is 3D
volume is L x W x H
area is L x W which has already been given to you so you just need to use the height given to you
38.28 x 11
Answer:
- 1
Step-by-step explanation:
Let the slope of one line be 's' , then according to the given condition that the slope of second line is negative reciprocal of the first , We obtain the slope of the second line as .
So, the product of both the slopes is given by
This shows that whatever the slopes may be if they are negative reciprocal of each other then their product will always be -1