Answer:
Net foreign lending would be equal to <u>$4 billion</u>.
Explanation:
This can be computed using the formula for computing the total output of an open economy as follows:
Y = C + G + I + NX .................................. (1)
Where;
Y = Total Output = $35 billion
C = Desired consumption = $15 billion
G = Government purchases = $10 billion
I = Desired investment = $6 billion
NX = Net foreign lending = ?
Substituting the values into equation (1) and solve for NX, we have:
$35 = $15 + $10 + $6 + NX
$35 - $15 - $10 - $6 = NX
NX = $4 billion
Therefore, net foreign lending would be equal to <u>$4 billion</u>.
First, you have to calculate the amount of tuition when the student reaches age 18. Do this by multiplying $11,000 by 1.07 each year from age 12 until it reaches age 18. Thus, 7 times.
At age 18: 16,508
At age 19: 17,664
At age 20: 18,900
At age 21: 20,223
Then, we use this formula:
A = F { i/{[(1+i)^n] - 1}}
where A is the monthly deposit each year, F is the half amount of the tuition each year illustrated in the first part of this solution, n is the number of years lapsed.
At age 18:
A = (16508/2) { 0.04/{[(1+0.04)^6] - 1}} = $1,244.389 deposit for the 1st year
Ate age 19
A = (17664/2) { 0.04/{[(1+0.04)^7] = $1,118 deposit for the 2nd year
At age 20:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $1,025 deposit for the 3rd year
At age 21:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $955 deposit for the 4th year
Answer: they will report an interest expense of $150000 in December 2020
Explanation:
firstly we calculate how much interest will be accumulated for the whole year so we are given a $5 million Dollar purchase which is the amount that will accumulate interest over time, then we have been told the company ha issued a 1 year installment note therefore we have a time frame.
so now we will calculate the yearly interest of $5 million :
$5 000000x12% = $600000 so the company will accumulate this interest yearly then we divide this amount by 12 to get the monthly interest.
$600000/12 = $ 50000 per month interest thereafter we will multiply the monthly interest of $50000 by 3 months which is months from October to December.
therefore the interest expense to be reported on the December 2020 income statement is $50000 x 3= $150000
Answer:
The speed of the car is 67.77 m/s and it is moving away from the observer.
Explanation:
The apparent frequency is given as
![f' = f\dfrac{ [v - vo]}{ [v - vs]}](https://tex.z-dn.net/?f=f%27%20%3D%20f%5Cdfrac%7B%20%5Bv%20-%20vo%5D%7D%7B%20%5Bv%20-%20vs%5D%7D)
Here
o is the observer
s is the source which is car
v is the speed of sound = 343 m/s
f = true frequency emitted by the car (when stationary)
f ' = 0.835 f
so
![f' = f\dfrac{ [v - vo]}{ [v - vs]}\\0.835 f= f\dfrac{ [v - vo]}{ [v - vs]}\\0.835 = \dfrac{ [343 - 0]}{ [343 - vs]}\\0.835=\frac{343}{343-x}\\x=-67.77 m/s](https://tex.z-dn.net/?f=f%27%20%3D%20f%5Cdfrac%7B%20%5Bv%20-%20vo%5D%7D%7B%20%5Bv%20-%20vs%5D%7D%5C%5C0.835%20f%3D%20f%5Cdfrac%7B%20%5Bv%20-%20vo%5D%7D%7B%20%5Bv%20-%20vs%5D%7D%5C%5C0.835%20%3D%20%5Cdfrac%7B%20%5B343%20-%200%5D%7D%7B%20%5B343%20-%20vs%5D%7D%5C%5C0.835%3D%5Cfrac%7B343%7D%7B343-x%7D%5C%5Cx%3D-67.77%20m%2Fs)
The speed of the car is 67.77 m/s and it is moving away from the observer.
