15p+15p+25p=30p+25p=55p
we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>
We know that at 8:00 a.m. there were t inches of snow in the ground.
At 5:00 p.m. there were 3t inches of snow in the ground.
Then the difference between the heights of the snow is:
3t- t = 2t
And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:
3t = 12in
t = (12in)/3 = 4 in
Replacing that in the difference of heights:
2t = 2*4in = 8in
From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
If you want to learn more about linear equations:
brainly.com/question/1884491
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1 kilogram (kg) equals to 1000 grams (g). Since you have 6.42 kilograms, divide 6.42 kilograms to 1000 grams. Your final answer is 6420 grams in total.
Hello from MrBillDoesMath!
Answer:
88
Discussion:
Angle Q is an inscribed angle so
measure angle Q = 44 =
(1/2) measure of intercepted arc.
In other words,
44 = 1/2 mST => multiply both sides by 2
m ST = 44*2 = 88
which is the second choice
Thank you,
MrB
<u>Step-by-step explanation:</u>
To prove:
Identities used:
......(1)
........(2)
.......(3)
Taking the LHS:
Using identity 1:
Using identities 2 and 3:
As, LHS = RHS
Hence proved
