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2 years ago

Help please..................

Mathematics

2 answers:

jasenka [17]2 years ago

7 0

The answer is : 43.7

serious [3.7K]2 years ago

3 0

Answer:

43.7

Step-by-step explanation:

4 secs on was 78.4 meters, 5 was 122.5, 122.5-78.8=43.7

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Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

5 0

3 years ago

Round the following as specified.<br> to the nearest thousandth

xenn [34]

Answer:

153.385

Step-by-step explanation:

After the dot it goes tenths,hundreds, then thousands

Image:

7 0

2 years ago

Can you answer number10 please I’m trying to help my sister

Deffense [45]

Answer:

544

Step-by-step explanation:

I added them together.

3 0

3 years ago

Read 2 more answers

Matt has answered 20/25 of the question on a test . What percent of test Questions has Matt answers

sergey [27]

you need to make the fraction to 100

100/25=

you multiply 20x4

6 0

3 years ago

Read 2 more answers

True or false? f (x) = 2 · (1/5)^x represents an exponential function growth.

nekit [7.7K]

Hi there!

$\large\boxed{\text{False.}}$

f(x) = 2(1/5)ˣ

Recall the form of an exponential function:

f(x) = a(b)ˣ where:

a = initial value

b = rate of decay/growth

If b > 1, the function is undergoing exponential growth. If b < 1, then the function is undergoing exponential decay.

1/5 < 1, so the function is undergoing exponential decay, not growth.

7 0

3 years ago