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Mashutka [201]
3 years ago
13

Find an equivalent expression to this: 3xy + 4x + 8 + ( -2 )​

Mathematics
1 answer:
Arlecino [84]3 years ago
7 0
3xy + 4x -16 ...... I hope that helps .
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Evaluate the expression below for x = 4 6 (x +7)
Drupady [299]

Answer:

D. 66

Step-by-step explanation:

6×(4+7)

6×11

=66

6 0
2 years ago
Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y

a)

we know that \int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1

therefore \int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1

on integrating we get

c=(1/6640)

b)

P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

on doing the integration we get

                        =0.37349

c)

marginal density of X is

f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx

on doing integration we get

f(y)=\frac{(y+40.5)}{83}

d)

P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

solve the above integration we get the answer

e)

P(X>20, 0

solve the above integration we get the answer

f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

4 0
3 years ago
Bryan bought 4 bags of peanuts from the grocery store. Each bag of has the
docker41 [41]

Answer:

141

Step-by-step explanation:

564 divided by 4 = 141

8 0
2 years ago
A cylindrical container with a radius of 5 cm and a height of 14 cm is completely filled with liquid. Some of the liquid from th
Flura [38]

Answer:

The remaining liquid has a volume of 345.4 cm³.

Step-by-step explanation:

To solve this question we first need to calculate the volume of each container.

Cylindrical:

Volume = h*pi*r² = 14*3.14*(5)² = 1099 cm³

Cone:

Volume = (1/3)*h*pi*r² = (1/3)*20*3.14*(6)² = 753.6 cm³

Since the liquid from the cylinder was transfered to the cone until the latter was full, then what remains in the cylinder is it's original volume minus the cone volume. So we have:

remaining liquid = 1099 - 753.6 = 345.4 cm³

4 0
3 years ago
Write the solution to the given inequality in interval notation
Kobotan [32]
You are right on the question
7 0
2 years ago
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