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weqwewe [10]
3 years ago
6

Which of the following conclusions can be drawn from JJ Thomson's cathode ray experiments?A.) Atoms contain electronsB.) Practic

ally all the mass of an atom is contained in its nucleusC.) Atoms contain protons, neutrons, and electronsD.) Atoms have positively charged nuclues surrounded by electron cloud
Chemistry
1 answer:
kari74 [83]3 years ago
3 0

Answer:

A.) Atoms contain electrons

Explanation:

J.J. Thomson conducted an experiment in which he took a gas at low pressure in a discharge tube and applied high voltage current. When he did so, he noticed that there are some particles emitting from cathode going towards the anode. <u>Then he concluded that they are negatively charged particles and coined them electrons.</u>

<u>Hence, out of the options:- A.) Atoms contain electrons is correct.</u>

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In Chromium-53, the "53" represents the
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The differemt isotopes that differ in atomic mass

Explanation:

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What is homologous series . Write it's characteristics
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Answer:

Homologous series is defined as a systematic order of structurally similar organic compound containing same functional group in their family and two adjacent members differ in their molecular formula by -CH2 unit.

Characteristics:

1.Various members of homologous series contain same functional group.

2.Various members of homologous series can be represented by common formula.

3. All members of a homologous series have almost similar chemical properties.

4. All members have common method of preparation.

5.Two successive members of homologous series have different chain length or difference in their molecular formula by -CH2 unit.

6.The members of homologous series show different physical properties.

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2 years ago
What powers explosions and fire
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5 0
3 years ago
Which of the following is an example of chemical energy being released or stored?
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C

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7 0
2 years ago
Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each
Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

C₃H₈(g) + O₂(g) → 3CO₂(g) + H₂O(l)

In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

C₃H₈(g) + O₂(g) → 3CO₂(g) + 4H₂O(l)

In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

The reaction is balanced.

Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

H has fix Nox equal to +1, and the molecule is neutral, so, calling x the Nox of C:

3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

6 0
3 years ago
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