Question

If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper?

Answer 1

consider the balanced equation ~~CuSO4 + Zn mc016-1.jpg ZnSO4 + Cu 

and this is the answer 79.63g

Answer 2

Answer : The theoretical yield of copper is, 79.375 grams

Explanation : Given,

Mass of copper(II) sulfate = 200 g

Molar mass of copper(II) sulfate = 159.6 g/mole

Molar mass of copper = 63.5 g/mole

First we have to calculate the moles of $CuSO_4$.

$\text{Moles of }CuSO_4=\frac{\text{Mass of }CuSO_4}{\text{Molar mass of }CuSO_4}=\frac{200g}{159.6g/mole}=1.25moles$

Now we have to calculate the moles of copper.

The balanced chemical reaction will be :

$CuSO_4+Zn\rightarrow ZnSO_4+Cu$

From the balanced chemical reaction, we conclude that

As, 1 mole of $CuSO_4$ react to give 1 mole of $Cu$

So, 1.25 moles of $CuSO_4$ react to give 1.25 moles of $Cu$

Now we have to calculate the mass of Cu.

$\text{Mass of }Cu=\text{Moles of }Cu\times \text{Molar mass of }Cu$

$\text{Mass of }Cu=(1.25mole)\times (63.5g/mole)=79.375g$

Therefore, the theoretical yield of copper is, 79.375 grams