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n200080 [17]
2 years ago
12

Part A: Solve the equation 5(x + 2) = 6x + 3x − 14, and show your work. (5 points)

Mathematics
1 answer:
Cerrena [4.2K]2 years ago
8 0

Answer:

x = 6

Step-by-step explanation:

Step 1 - Expand brackets via distributive property:

5(x + 2) = 6x + 3x - 14\\5(x) + 5(2) = 6x + 3x - 14\\5x + 10 = 6x + 3x - 14

Step 2 - Combine like terms:

5x + 10 = 6x + 3x - 14\\5x + 10 = 9x - 14

Step 3 - Use the addition property of equality to isolate the 9x:

5x + 10 = 9x - 14\\5x + 10 + 14 = 9x - 14 + 14\\5x + 24 = 9x

Step 4 - Use the subtraction property of equality to move the 5x over and isolate the 24:

5x + 24 = 9x\\5x + 24 - 5x = 9x - 5x\\24 = 4x

Step 5 - Use the division property of equality to simplify:

4x = 24\\\\\frac{4x}{4} = \frac{24}{4}\\\\x = 6

Hope this helps!

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2 years ago
What is 6,383 in expended form?<br>​
liberstina [14]

Answer:

expanded notation form:

 6,383 =

 6,000  

+ 300  

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expanded factors form:

   6,383 =

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+ 3 × 100  

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expanded exponential form:

 6,383 =

6 × 103

+ 3 × 102

+ 8 × 101

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Step-by-step explanation:

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2 years ago
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2 years ago
Use the rectangle hexagon with side length 10 meters to fill in the missing information
Vlada [557]

Answer:

A_h=150\sqrt{3}\ m^2

Step-by-step explanation:

<u>Regular Hexagon</u>

For the explanation of the answer, please refer to the image below. Let's analyze the triangle shown inside of the hexagon. It's a right triangle with sides x,y, and z.

We know that x is half the length of the side length of the hexagon. Thus

x=5 m

Note that this triangle repeats itself 12 times into the shape of the hexagon. The internal angle of the triangle is one-twelfth of the complete rotation angle, i.e.

\theta=360/12=30^o

Now we have \theta, the height of the triangle y is easily found by

\displaystyle tan30^o=\frac{x}{y}

Solving for y

\displaystyle y=\frac{x}{tan30^o}=\frac{5}{ \frac{1} {\sqrt{3} }}=5\sqrt{3}

The value of z can be found by using

\displaystyle sin30^o=\frac{x}{z}

\displaystyle z=\frac{x}{sin30^o}=\frac{5}{\frac{1}{2}}=10

The area of the triangle is

\displaystyle A_t=\frac{xy}{2}=\frac{5\cdot 5\sqrt{3}}{2}=\frac{25\sqrt{3}}{2}

The area of the hexagon is 12 times the area of the triangle, thus

\displaystyle A_h=12\cdot A_t=12\cdot \frac{25\sqrt{3}}{2}=150\sqrt{3}

\boxed{A_h=150\sqrt{3}\ m^2}

6 0
3 years ago
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