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igor_vitrenko [27]
3 years ago
7

What is the solution to the following system 4x+3y-z=-6

Mathematics
1 answer:
Aliun [14]3 years ago
3 0

Solve equation [2] for the variable  y  
 

<span> [2] y = 6x + 3z - 12 </span>

// Plug this in for variable  y  in equation [1]

<span><span>  [1] 4x + 3•(6x+3z-12) - z = -6 </span><span>  [1] 22x + 8z = 30 </span></span>

// Plug this in for variable  y  in equation [3]

<span><span>  [3] 8x + 2•(6x+3z-12) + 4z = 6 </span><span>  [3] 20x + 10z = 30 </span></span>

// Solve equation [3] for the variable  z  
 

<span> [3] 10z = -20x + 30 [3] z = -2x + 3</span>

// Plug this in for variable  z  in equation [1]

<span><span>  [1] 22x + 8•(-2x+3) = 30 </span><span>  [1] 6x = 6 </span></span>

// Solve equation [1] for the variable  x  

<span><span>  [1] 6x = 6</span>  <span>  [1] x = 1</span> </span>

// By now we know this much :

<span><span>  x = 1</span> <span>  y = 6x+3z-12</span> <span>  z = -2x+3</span></span>

<span>// Use the  x  value to solve for  z  
</span>

<span>   z = -2(1)+3 = 1 </span>

<span>// Use the  x  and  z  values to solve for  y  
</span><span><span>  y = </span>6(1)+3(1)-12 = -3 </span>

Solution :<span><span> {x,y,z} = {1,-3,1}</span> </span>
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