3 years ago

Let f(x)=4x-1 and g(x)=x2+1 Find (f•g)(7)

Mathematics

1 answer:

Helen [10]3 years ago

8 0

4x-1 28-1=27 x2+1 =55

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Express the negations of each of these statements so that all negation symbols immediately precede predicates. a) ∀x∃y∀zT(x, y,

Gnesinka [82]

Answer:

a) ∀x∃y ¬∀zT(x, y, z)

∀x∃y ∃z ¬T(x, y, z)

b) ∀x¬[∃y (P(x, y) ∨ Q(x, y))]

∀x∀y ¬ [P(x, y) ∨ Q(x, y)]

∀x∀y [¬P(x, y) ^ ¬Q(x, y)]

c) ∀x ¬∃y (P(x, y) ^ ∃zR(x, y, z))

∀x ∀y ¬(P(x, y) ^ ∃zR(x, y, z))

∀x ∀y (¬P(x, y) v ¬∃zR(x, y, z))

∀x ∀y (¬P(x, y) v ∀z¬R(x, y, z))

d) ∀x¬∃y (P(x, y) → Q(x, y))

∀x∀y ¬(P(x, y) → Q(x, y))

∀x∀y (¬P(x, y) ^ Q(x, y))

3 0

2 years ago

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Triangles J K L and X Y Z are shown. Angles K J L and Y X Z are right angles. The length of Y X is 10. The length of hypotenuse

pickupchik [31]

ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

<h3>What are Congruent Triangles?</h3>

Congruent triangles are triangles whose corresponding sides are congruent to each other.

The hypotenuse of triangle JKL(KL = 10) is congruent to a leg of triangle XYZ (YX = 10). This implies that they cannot be congruent triangles.

Therefore, ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

Learn more about congruent triangles on:

brainly.com/question/11457412