Answer:
l=10 cm
Step-by-step explanation:
In a rhombus, the diagonals are cut into identical lines at the intersection.
This way, I found the measures of the halves of the diagonals in a right triangle, knowing that the diagonals of the rhombus are perpendicular on each other.
I calculated that AO = AC/2= 8, and that BO=BD/2= 6, and then I applied pytagora's theorem in a quarter of the rhombus, which is the right triangle AOB, to find the length of a side
3 years
ar(n)=total a is the first number which is 7000 r is the common ratio which is 100%+2%=102 102 divided by 100 giving u 1.02(interest) so ar(n)=sum n is written as power.....and is the number of years so 7000*1.02(n)=(7000+420) 1.02(n)=7420/7000 1.02(n)=1.06 log10 1.02(n)=log10(1.06) ( multiply log10 with both) n=log10(1.06)/log10 (1.02) u get 2.94 which is round off to 3 so 3 years.. hope This helps :)
Answer:
B
Step-by-step explanation:
Here, we want to know at what values of b does the equation becomes not solvable
Now looking at the left hand side, we have;
2/(3-5bx) and also the right hand side bx + 1/3
For this expression if we insert b = 0, then automatically x cancels out on both sides of the equation and we shall be left with nothing to solve
HEXA = 6, 6 sides, thus the hexagon has 6 sides, each side is 4 cm long, thus that gives us a perimeter of 6 * 4 = 24.
![\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ p=24\\ a=3.5 \end{cases}\implies A=\cfrac{1}{2}(3.5)(24)\implies A=42](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20p%3D24%5C%5C%20a%3D3.5%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%283.5%29%2824%29%5Cimplies%20A%3D42)
Answer:
do we have to solve it or what cause I'm confused
