All categories

3 years ago

Solve 3(2x-5)-4x+8=-1

Mathematics

1 answer:

777dan777 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Step 1:

3 ( 2x - 5 ) - 4x + 8 = - 1

Step 2:

5x - 15 - 4x + 8 = - 1

Step 3:

x - 15 + 8 = - 1

Step 4:

x - 7 = - 1

Answer:

x = 6

Hope This Helps :)

You might be interested in

The graph of a sine function g(x) is presented below.

NISA [10]

Solution

To determine the vertical translation

We need to determine the amplitude

The amplitude is

$\frac{10-4}{2}=\frac{6}{2}=3$

Since the minimum is 4

Hence, the Vertical shift is 3+4 = 7

Part B

Given f(x) = 4 sin(θ - 45) + 8

The vertical translation is 8

3 0

1 year ago

Please help!!!!!!!!!!!!!!!! 100pts,

Helga [31]

QUESTION:

The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.

ANSWER:

Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–

P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.

Since there are 10 digits to choose from, we can assume that n = 10.

Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.

Now, plug these values into the formula and solve:

= 10!(10−5)!

= 10!5!

= 10⋅9⋅8⋅7⋅6

= 30240.

3 0

2 years ago

Elsa took out a 2-year loan to buy a car at 6% simple interest rate if she had to pay264 in interest how much principal did she

mina [271]

I = p * r * t
264 = p * .06 * 2
264 = .12p
Divide both sides by .12
p = $2200

5 0

3 years ago

100 points if u help

malfutka [58]

The answer is 87.12

Just check it once

6 0

3 years ago

Read 2 more answers

Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0

andreev551 [17]

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==> sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0 or sin(2x) = 0 or 2 cos(2x) + 1 = 0

sin(5x) = 0 or sin(2x) = 0 or cos(2x) = -1/2

sin(5x) = 0 ==> 5x = arcsin(0) + 2nπ or 5x = arcsin(0) + π + 2nπ

… … … … … ==> 5x = 2nπ or 5x = (2n + 1)π

… … … … … ==> x = 2nπ/5 or x = (2n + 1)π/5

sin(2x) = 0 ==> 2x = arcsin(0) + 2nπ or 2x = arcsin(0) + π + 2nπ

… … … … … ==> 2x = 2nπ or 2x = (2n + 1)π

… … … … … ==> x = nπ or x = (2n + 1)π/2

cos(2x) = -1/2 ==> 2x = arccos(-1/2) + 2nπ or 2x = -arccos(-1/2) + 2nπ

… … … … … … ==> 2x = 2π/3 + 2nπ or 2x = -2π/3 + 2nπ

… … … … … … ==> x = π/3 + nπ or x = -π/3 + nπ

(where n is any integer)

5 0

2 years ago