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2 years ago

5

a rectangle has an area of 40cm. the dimensions of the rectangle are multiplied to form a new rectangle with an area of 160cm. b

y what number were the dimensions multiplied?

1 answer:

denis-greek [22]2 years ago

4 0

The first rectangle has a length of 20cm and a width of 2cm for the area to be 40cm. so, the dimensions must be multiplied by 4 to equal 160cm.

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Will mark brainliest!!

wlad13 [49]

<span>Solve the system

9x = 27-9y
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Let's use the "elimination through addition/subtraction method.
Multiply the first equation by -1 so as to obtain +9y:

-9x = -27 + 9y
</span><span>20x= 71- 9y
--------------------

Add these 2 equations together:

</span>-9x = -27 + 9y
20x= 71- 9y
--------------------
<span> 11x = 44

Solve this for x: x = 44/11 = 4.

Now find y by subst. 4 for x in either of the original equations.

Using the second equation: </span><span>

</span>20x=71-9y
20(4) = 71 - 9y
80-71 = -9y
9 = -9y. Then y = -1.

The solution set is (4,-1).

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2 years ago

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Mademuasel [1]

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