Answer:
Height of shuttle at that instant = 1.17 miles
Step-by-step explanation:
Refer the given figure.
C is the position of rocket and B is the position of observer.
Here we need to find AC, that is the height of shuttle at that instant.
Using trigonometric rules on ΔABC, we have

Height of shuttle at that instant = AC = 1.17 miles
Distance= √((x2-x1)²+(y2-y1)²) = √((6-3)²+(0-2)²)=√(9+4)=√13 ≈ 3.61
Answer:
1/32
Step-by-step explanation:
This could be written as 
1/2 x 1/2 x 1/2 x 1/2 x 1/2
= 1/32, or 0.03125.
Answer:
720 MPH
Step-by-step explanation:
2700 miles / 3.75 hours = 720 MPH
2x77}{x} theis way is the best answee