Answer:x= 9
Step-by-step explanation:
-4(x+5) = 16
-4*x= -4x -4*5= -20
16 - -20= 36
-4x/-4= x 36/-4=9
The answer to your question is 0.125 Hope this helps! God bless
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
Answer:
f(g(x)) = 5(3x + 5) = 15x + 25
g(f(x)) = 3(5x) + 5 = 15x + 5
Step-by-step explanation:
Since you didn't say what you were trying to find, I'll give you a couple things you may have been trying to find.
f(g(x)) = 5(3x + 5) = 15x + 25
g(f(x)) = 3(5x) + 5 = 15x + 5