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3 years ago

Given that AC and BD are chords, apply the Intersecting Chord Theorem to set up an equation and solve for x.

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

8 0

Answer:

The value of x = 3 units

Step-by-step explanation:

Here, AC = 3 ,( 5x - 3)

BD = x , (x +9)

INTERSECTING CHORD THEOREM

It states that the products of the lengths of the line segments on each chord are equal.

Applying the theorem here, we get

$3( 5x - 3 ) = x (x +9)\\\implies 3(5x) - 3(3) = x(x) + 9 (x)\\or, 15x - 9= x^2 + 9x\\\implies x^2 + 9x - 15 x + 9 = 0\\or, x^2 -6x + 9 = 0$

Simplifying for the value of x , we get

$x^2 -6x + 9 = 0 \implies x^2 - 3x - 3x + 9 = 0\\x(x-3) -3(x -3) =0\\or, (x-3)(x-3) = 0$

or, x = 3

Hence, the value of x = 3 units

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SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

Find the vertex

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

8 0

3 years ago

Please help asap!!!! 53 points!

AfilCa [17]

The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.
The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:
(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.
So one form of the equation would be:
y = -1x - 2
Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)
and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3
so we get: y-k = -1 (x--5)...
y-3 = -(x+5)... therefore D) is the correct answer:

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3 years ago

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The interquartile range (IQR) for the data: 32,7,3,-5,1,8 , 10,36 is :

GenaCL600 [577]

Answer:

Your Interquartile range (IQR) would be 19.

Step-by-step explanation:

-5, 1, 3, 7, 8, 10, 32, 36

Median: 7.5

Lower quartile: 2

Upper quartile: 21

Interquartile range: 21 - 2 = 19

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3 years ago

What three consecutive integers equal -87?

olchik [2.2K]

Answer:

What three consecutive integers have a sum of 87? Which means that the first number is 28, the second number is 28 + 1 and the third number is 28 + 2. Therefore, three consecutive integers that add up to 87 are 28, 29, and 30. We know our answer is correct because 28 + 29 + 30 equals 87 as displayed above.

Step-by-step explanation:

Consecutive integers are as simple as 1, 2, 3!

Integers are consecutive if one follows another. How do we "jump" from one integer to the next? We add 1, right? 7, 8 and 9 are three consecutive integers. Add one to 7 to get 8 and add one more to get 9.

Now lets think about this in algebraic terms. Lets name these consecutive integers , x, y and z.

The problem tells us that their sum is -87. (Recall, "sum" is just a fancy word for the answer when we add.)

x+y+z = -87

Here is the trick! We need to rewrite this equation so that we have only one variable. Easy!

y is one more that x, so y= x+1

And z is one more than y, so z= y+1. But y is also equal to (x+1)! So z=y+1=(x+1)+1=x+2

Now we have a problem that we can solve! x+(x+1)+(x+2)=-87.

Combining term.: 3x+3=-87

Subtract 3 from both sides of the equation: 3x=84

Divide each side of the equation by 3: x=28

We have solved for x, but we are not done! We need to find y and z. I know you can do this. Remember y is one more than x and z is one more than y.

Check your work! Make sure these three consecutive numbers do in fact add up to -87.

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3 years ago

The equation of the given line is....?

liq [111]

Answer:y=3x+3

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3 years ago

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