Answer:
5: B:
6: B:
Explanation:
hope it helps thank me later if im correct!
Answer:
A 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N
Explanation:
The gravitational attraction between an object on the surface of a planet and the planet is given by the weight of the object
Therefore the force needed to be applied for an object to lift off the surface of a planet = The weight of the object
The weight of the object on the surface of a planet = m × g
Where;
m = The mass of the object
g = The strength of gravity on the planet's surface in N/kg
The given parameters are;
The mass of the person standing on a platform at the surface of Saturn, m = 60 kg
The strength of gravity on the surface of Saturn = 9 N/kg
Therefore, we have;
The weight of the person = The force greater than which the person would have to push on the surface of Saturn so as to Jump = The weight of the person on the surface of Saturn = 60 kg × 9 N/kg = 540 N
Therefore, for a 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N.
During the Gupta golden age, Aryabhata was known for discovering that Earth rotated on an axis.
Aryabhata was a professional at mathematics and astronomy. He calculated the value of pi, calculated the volume of a sphere and area of a triangle, characterized the model of the solar system, and many other things. While studying astronomy, Aryabhata came up with an assumption that Earth rotated on an axis while the heavens orbited around it.
Answer:
c. 25,000 frames/s
Explanation:
For computing the minimum frame rate for high speed first we have to determine the time by applying the following equation
![t = \frac{d}{s}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7Bd%7D%7Bs%7D)
![= \frac{0.2\ mm}{4.6\ m/s }](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.2%5C%20mm%7D%7B4.6%5C%20m%2Fs%20%7D)
![= \frac{0.2 \times 10 ^{-3}}{4.6\ m/s }](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.2%20%5Ctimes%2010%20%5E%7B-3%7D%7D%7B4.6%5C%20m%2Fs%20%7D)
![= 4.347 \times 10^{-5} sec](https://tex.z-dn.net/?f=%3D%204.347%20%5Ctimes%2010%5E%7B-5%7D%20sec)
Now the frame rate is
![Frame\ rate = \frac{1}{t}](https://tex.z-dn.net/?f=Frame%5C%20rate%20%3D%20%5Cfrac%7B1%7D%7Bt%7D)
![= \frac{1}{4.347 \times 10^{-5} sec}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B4.347%20%5Ctimes%2010%5E%7B-5%7D%20sec%7D)
= 23,000 frame per sec
≈ 25,000 frame per sec
First we have find the time then after finding out the time we calculate the frame time by applying the above formula so that the minimum frame rate could come
Well,
It really depends on thier temperature. But the answer is C) Heat would flow from both beakers.