Question

A scooter has a mass of 250. Kg. A constant force is exerted on it for 60.0 S. during the time the force is exerted, the scooter increases its speed from 6.00 m/s to 28.0 m/s. What is the change in momentum? What is the magnitude of the force exerted on the scooter?

Answer 1

Answer:

Explanation:

change in momentum = m ( v - u )   ;   m is mass , V is final velocity and u is initial velocity .

= 250 ( 28 - 6 )

= 5500. N.s

for calculating magnitude of force we shall apply the concept of impulse

Impulse = F X t = m( v-u )    ;   F is force applied for time t .

F x 60 = 5500

F = 91.67 N .

force exerted = 91.67 N .