Question

a student whose normal weight is 500 newtons stands on a scale in a elevator. displacement, velocity, and acceleration are upward. What is the acceleration for each 5 second interval.

Answer 1

Answer:

0-5s   a =  0 m/s^2

5-10 s  a = 3.92m/s^2

10-15s   a = o m/s^2

15-20s  a = -3.92 m/s^2

Explanation:

From the given graph we can have following information:

0-5 seconds - 500 Newtons

5-10 seconds - 700 Newtons

10-15 seconds - 500 Newtons

15-20 seconds - 300 Newtons"

Acceleration for each 5 second is given as

0-5s =  0 m/s^2 because force remain constant  

5-10 s

$= f_{net} = ma$

= 700-500 =51×a

a = 3.92m/s^2

10-15s = o m/s^2 as force remain constant

15-20s

$= f_{net} =ma$

= 300-500 = 51a

a = -3.92 m/s^2

Answer 2

0-5 seconds and 10-15 seconds: zero acceleration, constant velocity (may be zero)

5-10 seconds: upward acceleration, velocity increasing upwards or decreasing downwards

15-20 seconds: downward acceleration, velocity decreasing upward or increasing downward