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Evgesh-ka [11]
3 years ago
10

If a 2 kg ball is moving at 6 m/s to the right and then hits a wall and bounces back at - 4 m/s (left), what is the change in mo

mentum (in kg*m/s)?
Physics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

Explanation:

Givens

delta mv = ?

m = 2 kg

vi = 6 m/s   right is positive

vf = - 4 m/s  left

Formula

delta mv = m (vf - vi)

Solution

delta mv = 2 * (-4 - 6)

delta mv = 2 * - 10

delta mv = - 20 kg m/s

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Think about a hot air balloon, as the flames heat the gases in the balloon, the volume of the gases increases. At constant press
otez555 [7]

Scientific law

Scientific laws are statements of facts produced after observed events of nature. There are usually no exceptions to how the outcome of these events unravels. Laws explain HOW nature works.

Explanation:

ON THE OTHER HAND, Theories are usually blanket principles, usually overarching, on how nature has been observed to work. Theories can evolve over time as more information is discovered, but laws are more or less static.   Theories explain WHY we see nature to behave in a certain way.

In the case of this question it is scientific law that if a fluid is heated, it becomes less dense as its temperature rises.

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5 0
4 years ago
Mrs. Martin’s drive to school is 25 miles from her house. It takes her half an hour to get there. The speed limit is 40 mph. Was
oee [108]

Answer:

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7 0
3 years ago
Bill is farsighted and has a near point located 121 cm from his eyes. Anne is also farsighted, but her near point is 74.0 cm fro
Arada [10]

Answer:

Explanation:

The lens equation is

1 / f = 1 / di + 1 / do

Where

f is focal length

di is the image distance

do is the object distance

Both Annie and Billy use a glass whose near point is 25cm

Then, the object distance is

do = 25 - 2 = 23cm

The have the same object distance.

Let find the vocal length of bills eye

Given that,

Bill near point is 121cm and distance of the glass from the eye is 2cm

Then,

Image distance of bill is

di_B = -(121-2) = -119cm

object distance do = 23cm

Then,

1 / f_B = 1 / di_B + 1 / do

1 / f_B = -1 / 119 + 1 / 23

1 / f_B = -119^-1 + 23^-1

1 / f_B = 0.0351

Then, f_B = 28.51 cm

Also, let find Annie focal length

Given that,

Annie near point is 74 cm and distance of the glass from the eye is 2cm

Then,

Image distance of Annie is

di_A = -(74-2) = -72cm

object distance do = 23cm

Then,

1 / f_A = 1 / di_A + 1 / do

1 / f_A = -1 / 72 + 1 / 23

1 / f_A = -72^-1 + 23^-1

1 / f_A = 0.02959

Then, f_A = 33.8 cm

Distance of object from the lens when Annie uses Billy glass

Then,

1 / f_B = 1 / di_A + 1 / do

1 / 28.51 = -1 / 72 + 1 / do

28.51^-1 = -72^-1 + do^-1

do^-1 = 28.51^-1 + 72^-1

do^-1 = 0.048964

do = 20.42 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_A = 20.42 + 2 = 22.42cm

do_A = 22.42 cm

Distance of object from the lens when Billy uses Annie glass

Then,

1 / f_A = 1 / di_B + 1 / do

1 / 33.8 = -1 / 119 + 1 / do

33.8^-1 = -119^-1 + do^-1

do^-1 = 33.8^-1 + 119^-1

do^-1 = 0.03799

do = 26.32 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_B = 26.32 + 2 = 28.32 cm

do_B = 28.32 cm

7 0
3 years ago
(I) A novice skier, starting from rest, slides down an icy frictionless 8.0° incline whose vertical height is 105 m. How fast is
Vlad1618 [11]

Answer:

v = 45.37 m/s

Explanation:

Given,

angle of inclination = 8.0°

Vertical height, H  = 105 m

Initial K.E. = 0 J

Initial P.E. = m g H

Final PE = 0 J

Final KE = \dfrac{1}{2}mv^2

Using Conservation of energy

KE_i + PE_i + KE_f + PE_f

0 + m g H = \dfrac{1}{2}mv^2 + 0

v = \sqrt{2gH}

v = \sqrt{2\times 9.8 \times 105}

v = 45.37 m/s

Hence, speed of the skier at the bottom is equal to v = 45.37 m/s

3 0
3 years ago
What are the five basic postulates of kinetic-molecular theory?
lesantik [10]

Explanation:

The five basic postulate of kinetic molecular theory includes:

1) All gases consist of large amount and numbers of tiny particles that are far apart from each other and also relative to their size.

2) The collisions between gas particles and gas particles against container walls is refer to as  elastic collision.

3) All gas particles are in a continuous random and rapid motion. They possess kinetic energy which is energy of motion.

4) There are no attractive force between gas particles.

5) The temperature of a gas depends on the average kinetic energy of the gas particle.

8 0
3 years ago
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