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vodomira [7]
3 years ago
14

What do you call the height of a wave?

Physics
2 answers:
balandron [24]3 years ago
7 0
Answer : C) Amplitude
Lina20 [59]3 years ago
5 0

Answer:

amplitude is the answer

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If an object has a mass of 20 grams and a volume of 40 cm3, what is its density in g/cm3?
alexgriva [62]
20/40=0.5 g/cm^3 becuase, mass/volume=density.
8 0
2 years ago
Ana walks from 4 m to 200 cm. Which of the following statements is true about
Gemiola [76]
Distance=2m

because 200cm = 2m
so 4m-2m=2m
3 0
3 years ago
Use a(t) = -32 feet per second per second as the acceleration due to gravity. (Neglect air resistance.) -With what initial veloc
Kitty [74]

Answer:

u= 187.61 ft/s

Explanation:

Given that

g= - 32 ft/s²

The maximum height ,h= 550 ft

Lets take the initial velocity = u ft/s

We know that

v²=u² + 2 g s

v=final speed ,u=initial speed ,s=height

When the object reach at the maximum height then the final speed of the object will become zero.

That is why

u²= 2 x 32 x 550

u²= 35200

u= 187.61 ft/s

That is why the initial speed will be 187.61 ft/s

7 0
3 years ago
Read 2 more answers
Blue light of wavelength λ passes through a single slit of width d and forms a diffraction pattern on a screen. If we replace th
ololo11 [35]

Answer:

We can retain the original diffraction pattern if we change the slit width to d) 2d.

Explanation:

The diffraction pattern of a single slit has a bright central maximum and dimmer maxima on either side. We will retain the original diffraction pattern on a screen if the relative spacing of the minimum or maximum of intensity remains the same when changing the wavelength and the slit width simultaneously.

Using the following parameters: <em>y</em> for the distance from the center of the bright maximum to a place of minimum intensity, <em>m</em> for the order of the minimum, <em>λ </em>for the wavelength, <em>D </em>for the distance from the slit to the screen where we see the pattern and <em>d </em>for the slit width. The distance from the center to a minimum of intensity can be calculated with:

                                                    y\approx\frac{m\lambda D}{d}

From the above expression we see that if we replace the blue light of wavelength λ by red light of wavelength 2λ in order to retain the original diffraction pattern we need to change the slit width to 2d:

<em>                                                 </em>y\approx\frac{m\lambda D}{d} =\frac{m2\lambda D}{2d}

7 0
3 years ago
How far apart (in mm) must two point charges of 70.0 nC (typical of static electricity) be to have a force of 1.30 N between the
Sever21 [200]

Answer:r=5.824 mm

Explanation:

Given

Charge q_1=70 nC

q_2=70 nC

Force between them F=1.30 N

Electrostatic Force is given by

F=\frac{kq_1q_2}{r^2}

where q_1 and q_2 are the charge on the Particles

r=distance between them

k=Coulomb\ constant =9\times 10^9 N-m^2/C^2

1.3=\frac{9\times 10^9\times 70\times 70\times 10^{-18}}{r^2}

r^2=\frac{9\times 10^9\times 70\times 70\times 10^{-18}}{1.3}

r=\sqrt{33.923\times 10^{-6}}

r=5.824\times 10^{-3}

r=5.824 mm

5 0
3 years ago
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