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labwork [276]
3 years ago
11

Sam is pulling a box up to the second story of his apartment via a string. The box weighs 16.5 kg and starts from rest on the gr

ound. Sam is pulling so that the velocity of the box is increasing by 2.6 m/s every second.
How long until the box reaches a height of 13.2 m?
Physics
1 answer:
Nitella [24]3 years ago
8 0

Answer:

3.19 s

Explanation:

We know,

s = ut + ( 1/2 * a * t^2 )

13.2 = 0*t + ( 1/2 * 2.6 * t^2 )

t^2 = 13.2/1.3 = 10.1538

t = 3.19

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The race car was was moving for 3.7 hours and during that time moved 500 miles east. What is the speed? What is the velocity?
vaieri [72.5K]

Speed:

v = \frac{500 \,\,\mbox{miles}}{3.7 \,\,\mbox{h}}\approx 135.14 mph

Velocity:

Velocity os speed with director (an oriented vector):

The velocity is 135.14 mph in the direction east

8 0
3 years ago
01. Um carrinho de massa 10 kg é empurrado, horizontalmente, sobre uma superfície plana horizontal, com força constante de 20 N.
Lostsunrise [7]

Responder:

<h2>D. 1.5m / s² </h2>

Explicación:

Usaremos la segunda ley de movimiento de Newton para resolver esta pregunta. De acuerdo con el teorema

es la suma de las fuerzas que actúan sobre el cuerpo a lo largo de la horizontal. Las dos fuerzas son la fuerza móvil (Fm) y la fuerza de fricción (Ff).

Fm = 20 N y Ff = 5 N

\sum Fx = ma_x\\\sum Fx = Fm - Ff\\\sum Fx  = 20N - 5N\\\sum Fx  = 15N

m es la masa del cuerpo = 10 kg

El parámetro requerido es cuál es la aceleración del cuerpo a lo largo de la horizontal.

De la ecuación 1;

a_x = \sum Fx/m\\\\a_x = 15/10\\\\a_x = 1.5m/s^2

Por lo tanto, la aceleración del carro es de 1.5 m / s²

3 0
4 years ago
What are moana's hobbies
crimeas [40]
The movie? Or the book
4 0
3 years ago
How much would a 70.0-kg person weigh on Mercury?
Natalija [7]

As weight =w =mg

g= gravitational acceleration on mercury = 3.7m/sec2

Mass of person =m= 70 kg

So w =(70kg)(3.7m/sec2)

w= 259 kgm/sec2

W= 259 N

6 0
3 years ago
A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. How far away is the cliff? The speed of soun
ella [17]

Answer:

480.2 m

Explanation:

The following data were obtained from the question:

Speed of sound (v) = 343 m/s.

Time (t) = 2.8 s

Distance (x) of the cliff =?

The distance of the cliff from the woman can be obtained as follow:

v = 2x /t

343 = 2x /2.8

Cross multiply

2x = 343 × 2.8

2x = 960.4

Divide both side by the coefficient of x i.e 2

x = 960.4/2

x = 480.2 m

Therefore, the cliff is 480.2 m away from the woman.

4 0
3 years ago
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