<span>The DISTANCE travelled is 35.0 m. The DISPLACEMENT is 25.0 m south
</span>
Answer:
1) Vp = 127.36 m/s
2) According to the reference given: 252.17°
Explanation:
For the first part, we know that
So, the speed of the plane respect to ground is:
Vp = 127.36 m/s
For the second part, we calculate the angle:
on the third quadrant. According to the reference given, we need to make 270° - α, so:
The final angle is 252.17°
The question is how far not how for
Answer:
101.1 m
Explanation:
From the kinematics equations
s=ut-0.5gt^{2} but since u=o and the negative implies the distance is downwards then
s=0.5gt^{2} where s is the distance, u is initial speed, t is time, g is acceleration due to gravity
s=0.5*9.81*4.54^{2}=101.099898
\approx 101.1 m
A.
accept new and different ideas.
Answer:
i) 24.5 m/s
ii) 30,656 m
iii) 89,344 m
Explanation:
Desde una altura de 120 m se deja caer un cuerpo. Calcule a 2.5 s i) la velocidad que toma; ii) cuánto ha disminuido; iii) cuánto queda por hacer
i) Los parámetros dados son;
Altura inicial, s = 120 m
El tiempo en caída libre = 2.5 s
De la ecuación de caída libre, tenemos;
v = u + gt
Dónde:
u = Velocidad inicial = 0 m / s
g = Aceleración debida a la gravedad = 9.81 m / s²
t = Tiempo de caída libre = 2.5 s
Por lo tanto;
v = 0 + 9.8 × 2.5 = 24.5 m / s
ii) El nivel que el cuerpo ha alcanzado en 2.5 segundos está dado por la relación
s = u · t + 1/2 · g · t²
= 0 × 2.5 + 1/2 × 9.81 × 2.5² = 30.656 m
iii) La altura restante = 120 - 30.656 = 89.344 m.