<span>2002 seconds, or 33 minutes, 22 seconds.
First, let's calculate how many joules it will take to lift 78 kg against gravity for 1100 meters. So:
78 kg * 9.8 m/s^2 * 1100 m = 840840 kg*m^2/s^2
Now a watt is defined as kg*m^2/s^3, so a division of the required joules should give us a convenient value of seconds. So:
840840 kg*m^2/s^2 / 420 kg*m^2/s^3 = 2002 seconds.
And 2002 seconds is the same as 33 minutes, 22 seconds.</span>
Answer:111.63 joules
Explanation:
Kinetic energy=(massx(velocity)^2)/2
Kinetic energy=(6×(6.1)^2)/2
Kinetic energy=(6×37.21)/2
Kinetic energy=223.26/2
Kinetic energy=111.63 joules
Answer:
The linear velocity of the object is 8.71 m/s.
Explanation:
Given;
mass of the object, m = 1 kg
radius of the circle, r = 3.3 meters
centripetal force, F = 23 N
Centripetal force is given by;
where;
v is the linear velocity of the object
Therefore, the linear velocity of the object is 8.71 m/s.
The sprinter experiences muscle cramps and a stray dog on the track from A to B, followed immediately by acute nausea and a gaggle of news photographers from B to C.
If none of these selections appears on the list of choices, then perhaps we can do better if you'll permit us a glance at the picture that accompanies the question, even if you still don't let us see the choices.
