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4 years ago

What is friction and how does it affect objects in motion?

2 answers:

4 0

Friction is an important force because it is a force that affects motion. This force exerted by the surface of an object when another object moves against it is the result of molecular attractions between the objects' surfaces, and works in the direction opposite to the direction of the motion. hope this helps you.

lesantik [10]4 years ago

3 0

Friction is a force. A resistance force that tries to slow down and stop objects in motion. The difference between friction and air resistance is that friction acts on surfaces. For example, if I were skateboarding on a rough surface, more friction would occur so I would travel slower. If I were skareboarding on ice, I would go faster because there is much less friction to slow me down. Hope that helps:)

You might be interested in

A car accelerates from rest at 5.75m/s2 for 4.4 sec when it runs out of pavement and runs into some mud. In the mud it accelerat

just olya [345]

Answer:

113.85 m

Explanation:

When the car is on the pavement:

v₀ = 0 m/s

a = 5.75 m/s²

t = 4.4 s

Find: Δx and v

Δx = v₀ t + ½ at²

Δx = (0 m/s) (4.4 s) + ½ (5.75 m/s²) (4.4 s)²

Δx = 55.66 m

v = at + v₀

v = (5.75 m/s²) (4.4 s) + 0 m/s

v = 25.3 m/s

When the car is in the mud:

v₀ = 25.3 m/s

v = 0 m/s

a = -5.5 m/s²

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (25.3 m/s)² + 2 (-5.5 m/s²) Δx

Δx = 58.19 m

The total displacement is therefore:

55.66 m + 58.19 m = 113.85 m

4 0

4 years ago

What is the mass of an object traveling at 20 m/s with a kinetic energy of 4000 J?

valentinak56 [21]

Answer:

20 kg

Explanation:

Kinetic energy=½*Mass * velocity²

4000= ½* m*20²

8000=400m

m=8000/400

m=20 kg

5 0

3 years ago

I will give you BRAINILIEST!!!!!!!!! AND 15 POINTS

Zigmanuir [339]

Hello.

The best answer would be A.Rift Valley.

It forms when l tectonical plates move away froem each other.

Have a nice day :)

4 0

3 years ago

The brakes on your automobile are capable of creating a deceleration of 4.9 m/s2. If you are going 149 km/h and suddenly see a s

UNO [17]

Answer:

You need at least 2.8 s to slow down your car to 100 km/h. If we add reaction time (≅0.3 s), you will need 3.1 s.

Explanation:

Hi there!

The equation of velocity for an object moving in a straight line is the following:

v = v0 + a · t

Where:

v = velocity at time t.

v0 = initial velocity.

a = acceleration.

t = time.

We have to find the time at which the velocity is 100 km/h with a decceleration of 4.9 m/s² and an initial velocity of 149 km/h. Let´s first convert km/h into m/s:

149 km/h · (1000 m / 1 km) · ( 1 h / 3600 s) = 41.4 m/s

100 km/h · (1000 m / 1 km) · ( 1 h / 3600 s) = 27.8 m/s

Now, let´s solve the equation of velocity for the time:

v = v0 + a · t

(v - v0) / a = t

Replacing with the data:

(27.8 m/s - 41.4 m/s) / -4.9 m/s² = t

Notice that the acceleration is negative because you are slowing down.

t = 2.8 s

You need at least 2.8 s to slow down your car to 100 km/h. If we add reaction time (≅0.3 s), you will need 3.1 s.

6 0

3 years ago

An object of mass 1.0 kg is at rest on a smooth inclined plane with height h, length 8 m,

TEA [102]

The coefficient of kinetic friction for the rough horizontal surface is 0.66.

The given parameters;

mass of the object, m = 1 kg
length of the inclined plane, L = 8 m
angle of inclination of the plane, θ = 30⁰
distance traveled before hitting the spring, d₁ = 4 m
distance traveled after hitting the spring, d₂ = 1.3 m
the spring constant, k = 26.5 N/m

Apply work-energy theorem; the work done the force of friction is equal to the energy stored in the spring.

$F_kd_1 = \frac{1}{2} kd_2^2\\\\\mu_kmg cos(\theta)d_1 = \frac{1}{2} kd_2^2\\\\\mu_k(1 \times 9.8 \times cos(30)\times 4) = \frac{1}{2} \times 26.5 \times (1.3)^2\\\\33.95\mu_k = 22.39\\\\\mu_k = \frac{22.39}{33.95} \\\\\mu_k = 0.66$

Thus, the coefficient of kinetic friction for the rough horizontal surface is 0.66.

Learn more here:brainly.com/question/10063455

4 0

3 years ago