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azamat
3 years ago
6

A city bus travels 6 blocks east and 8 blocks north. Each block is 100 m long. If the bus travels this distance in 15 minutes, w

hat is the average speed of the bus (m/s)?
Physics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

The average speed of the bus, v = 1.55 m/s

Explanation:

Given that,

Number of blocks traveled by bus towards east = 6

Number of blocks traveled by bus towards north = 8

Length of each block = 100 m

Distance traveled by bus towards east 6 x 100 = 600 m

Distance traveled by bus towards north 8 x 100 = 800 m

The total distance traveled, d = 600 + 800 = 1400

Time taken by the bus to travel is, t = 15 minutes

The velocity is given by the formula

                                  v = d/t  m

Substituting the values in the above equation

                                   v = 1400 m /(15 x 60) s

                                      = 1.55 m/s

Hence, the average speed of the bus, v = 1.55 m/s

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The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .
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Answer: 90\°

Explanation:

The Compton Shift \Delta \lambda in wavelength when the photons are scattered is given by the following equation:

\Delta \lambda=\lambda_{c}(1-cos\theta)     (1)

Where:

\lambda_{c}=2.43(10)^{-12} m is a constant whose value is given by \frac{h}{m_{e}c}, being h the Planck constant, m_{e} the mass of the electron and c the speed of light in vacuum.

\theta) the angle between incident phhoton and the scatered photon.

We are told the maximum Compton shift in wavelength occurs when a photon isscattered through 180\°:

\Delta \lambda_{max}=\lambda_{c}(1-cos(180\°))     (2)

\Delta \lambda_{max}=\lambda_{c}(1-(-1))    

\Delta \lambda_{max}=2\lambda_{c}     (3)

Now, let's find the angle that will produce a fourth of this maximum value found in (3):

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)      (4)

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)      (5)

If we want \frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}, 1-cos\theta   must be equal to 1:

1-cos\theta=1   (6)

Finding \theta:

1-1=cos\theta

0=cos\theta  

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\theta=90\°    This is the scattering angle that will produce \frac{1}{4}\Delta \lambda_{max}      

7 0
3 years ago
What is the total number of pounds of carbon dioxide that 2 trees remove from the air each<br> year?
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If a range hood removes contaminants at a flow rate of F liters of air per​ second, then the percent P of contaminants that are
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Explanation:

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Therefore, the minimum value of P is 32.78 and maximum value of P is 96.38.

3 0
3 years ago
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