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Leto [7]
3 years ago
11

What is the expanded form of this number? 503.208 (Trying to help my sister do math!)

Mathematics
1 answer:
Blababa [14]3 years ago
3 0

Answer:

500+3+ .200+.008

Step-by-step explanation:

You add 500 and 3 then after you get your number add .200 lastly add .008.

when expanding numbers you need to know what place value it's in so that you k ow where to put the zeros.

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Use long division to find the quotient below.
Tems11 [23]

Answer:

Step-by-step explanation:

2

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[Ans]

7 0
4 years ago
2x^2+x-1=2^are^x=-3/2 or x=
jenyasd209 [6]
The second answer is x=1
4 0
3 years ago
Which is an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12?
Bond [772]

Answer:

An equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

  • y=-\frac{1}{5}x+\frac{13}{5}

Step-by-step explanation:

Given the equation

5x - y = 12

converting the line into the slope-intercept form y = mx+b, where m is the slope

-y = 12-5x

y = 5x-12

The slope of the line = m = 5

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

Therefore, the slope of new line = – 1/m = -1/5 = -1/5

Using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting the slope of new line = -1/5 and (-2, 3)

y-y_1=m\left(x-x_1\right)

y-3=-\frac{1}{5}\left(x-\left(-2\right)\right)

y-3=-\frac{1}{5}\left(x+2\right)

Add 3 to both sides

y-3+3=-\frac{1}{5}\left(x+2\right)+3

y=-\frac{1}{5}x+\frac{13}{5}

Therefore, an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

  • y=-\frac{1}{5}x+\frac{13}{5}
5 0
3 years ago
If x€{-2,-1,0,1,2,3,4,5} find the solution set 7-x>0 ii 3-4x>-2 vi 3x+4>-2​
maw [93]

Answer:

i) {-2 , -1 , 0 , 1  ,2 , 3 , 4 , 5}

ii) {-2 , -1 , 0 , 1}

iii) {-1 , 0 , 1  ,2 , 3 , 4 , 5}

Step-by-step explanation:

i) 7 - x > 0

⇔ 7 > x

⇔ x < 7

⇔ x ∈ {-2 , -1 , 0 , 1  ,2 , 3 , 4 , 5}

____________________________

ii) 3 - 4x > -2

⇔ 3 + 2 > 4x

⇔ x < 5/4

⇔ x ∈ {-2 , -1 , 0 , 1}

____________________________

iii) 3x + 4 > -2​

⇔ 3x  > -2​ - 4

⇔ 3x  > -6

⇔ x  > -6/3

⇔ x  > -2

⇔ x ∈ {-1 , 0 , 1  ,2 , 3 , 4 , 5}

8 0
2 years ago
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