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Leto [7]
3 years ago
11

What is the expanded form of this number? 503.208 (Trying to help my sister do math!)

Mathematics
1 answer:
Blababa [14]3 years ago
3 0

Answer:

500+3+ .200+.008

Step-by-step explanation:

You add 500 and 3 then after you get your number add .200 lastly add .008.

when expanding numbers you need to know what place value it's in so that you k ow where to put the zeros.

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Someone help me with this
Alex

Answer:

y=7.5x, y=9.25x, y=6x

Step-by-step explanation:

on the first table we have for 2 tikets $ 15 so the price for one ticket (also known as unit price) is 15/2= $ 7.5

the equation for the price of ticket must be

y= 7.5 x (where y is price you pay for x number of tikets)

on the second table you can pick that you have $37 for 4 tikets so unit price is 37/4= $9.25 per one ticket

y=9.25x

last table $12 for 2 tikets so for one ticket is 12/2=$6

y=6x

7 0
3 years ago
Read 2 more answers
Please I really need help with these
MrRissso [65]

Answer:

Idk lol

Step-by-step explanation:

8 0
3 years ago
Please help and ill give you brainliest and please don't just say something i lov youu and ill giv you points
ch4aika [34]

Answer:

1. 2(x+3)

2.x-3

3.2(x-3)

4.2-3x

5.x2+3

6.3-2

7.3+2

8.3x-2

9.3/x

10.x/3

Step-by-step explanation:

5 0
3 years ago
WhT is the relationship between the 6s in the number 660,472
AveGali [126]
There next to each other
4 0
3 years ago
Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0
cestrela7 [59]
When n=0, you have

4^0=1\equiv3(0)+1=1\mod9

Now assume this is true for n=k, i.e.

4^k\equiv3k+1\mod9

and under this hypothesis show that it's also true for n=k+1. You have

4^k\equiv3k+1\mod9
4\equiv4\mod9
\implies 4\times4^k\equiv4(3k+1)\mod9
\implies 4^{k+1}\equiv12k+4\mod9

In other words, there exists M such that

4^{k+1}=9M+12k+4

Rewriting, you have

4^{k+1}=9M+9k+3k+4
4^{k+1}=9(M+k)+3k+3+1
4^{k+1}=9(M+k)+3(k+1)+1

and this is equivalent to 3(k+1)+1 modulo 9, as desired.

3 0
3 years ago
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