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USPshnik [31]
4 years ago
8

A car was traveling at a constant speed of 20m/s overcomes a constant frictional resistant of 300newton.. What is the horse powe

r of the engine? (take 1hp=3/4kw) ​
Physics
1 answer:
nadezda [96]4 years ago
8 0

Answer:

8 hp

Explanation:

Power = work / time

P = W/t

Work = force × distance

W = Fd

Substituting:

P = Fd/t

P = Fv

Given that F = 300 N and v = 20 m/s:

P = (300 N) (20 m/s)

P = 6000 W

P = 6 kW

Converting to horse power:

6 kW × (1 hp / ¾ kW) = 8 hp

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In the absence of a gravitational force, the weight of a body is?
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0

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its b

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3 years ago
4.1 A steel spur pinion has a pitch of 5 teeth/in, 20 full-depth teeth, and a 20° pressure angle. The pinion runs at a speed of
Vesnalui [34]

Answer:

15.07 ksi

Explanation:

Given that:

Pitch (P) = 5 teeth/in

Pressure angle (\Phi) = 20°

Pinion speed (n_p ) = 2000 rev/min

Power (H) = 30 hp

Teeth on gear (N_G) = 50

Teeth on pinion (N_p) = 20

Face width (F) = 1 in

Let us first determine the diameter (d) of the pinion.

Diameter (d) = \frac{N}{P}

=\frac{20}{5}

= 4 in

From the values of Lewis Form Factor Y for (n_p ) = 20 ; at 20°

Y = 0.321

To find the velocity (V); we use the formula:

V = \frac{\pi d n_p}{12}

V = \frac{\pi *4*2000}{12}

V = 2094.40 ft/min

For cut or milled profile; the velocity factor (K_v) can be determined as follows:

K_v = \frac{2000+V}{2000}

K_v = \frac{2000+2094.40}{2000}

= 2.0472

However, there is need to get the value of the tangential load(W^t), in order to achieve that, we have the following expression

W^t=\frac{T}{\frac{d}{2} }

W^t = \frac{63025*H}{\frac{n_pd}{2}}

W^t = \frac{63025*30}{2000*\frac{4}{2}}

W^t = 472.69 lbf

Finally, the bending stress is calculated via the formula:

\sigma = \frac{K_vW^tp}{FY}

\sigma = \frac{2.0472*472.69*5}{1*0.321}

\sigma = 15073.07 psi

\sigma = 15.07 ksi

∴ The estimate of the bending stress = 15.07 ksi

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