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ValentinkaMS [17]
3 years ago
8

A few Physics questions regarding circuits and electricity.

Physics
1 answer:
Lunna [17]3 years ago
6 0

Answer:

7.series

Explanation:

in parallel is like if one bulb stops work all the others will stop too

in series it remains constant or it wont change throughout a series circuit

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10 poin<br> What is the momentum of a 25kg cart traveling left with a velocity of 10<br> m/s?
Mashutka [201]
250 kg*m/s
Momentum is found by multiplying mass by velocity
25*10=250
7 0
3 years ago
Please help me Calculate the total energy stored in the capacitor​
Neko [114]

La fórmula: P = W/t  ó  W = P x t. donde:

P = potencia

W = trabajo

t = tiempo

Otra fórmula de potencia es: P= I x V

Proceso de carga de un capacitor - condensador

Una fórmula muy importante que también hay que tener en cuenta es: V = q/C que indica que el voltaje es proporcional a la carga que hay en un condensador.

De la fórmula de potencia P= I x V y considerando que la corriente es constante (corriente continua), entonces la potencia es proporcional al voltaje.  Si el voltaje aumenta en forma lineal, la potencia aumentará igual. Ver el siguiente diagrama.

Como la potencia varía en función del tiempo, no se puede aplicar la fórmula W = P x t, para calcular la energía transferida. Pero observando el gráfico, se ve que esta energía se puede determinar midiendo el área bajo la curva de la figura.

Energía Almacenada en un Condensador - Capacitor

 

El área bajo la curva es igual a la mitad de la potencia en el momento “t”, multiplicada por “t”.

Entonces: W = (P x t) / 2. Pero se sabe que P = V x I. Si se reemplaza esta última fórmula en la anterior se obtiene: W = (V x I x t) / 2, y como I x t = CV = Q, entonces para saber cuanta energía (W) hay en un condensador usamos una de las siguientes fórmulas:

W = (CV2/2) julios

W = (QV/2) julios

W  = (Q2/2C) julios

, donde:

W = Trabajo (Energía) en julios

C = Capacidad en faradios

V = voltaje en voltios en los extremos del condensador

Q = carga del condensador

3 0
3 years ago
Read 2 more answers
The motor winds in the cable with a constant acceleration, such that the 20-kg crate moves a distance s = 6 m in 3 s, starting f
Marta_Voda [28]

Answer:

85 N

Explanation:

Given that crate mass = 20kg

Distance = 6m

Time = 3 seconds

Coefficient of kinetic friction = 0.3

We begin by calculating for acceleration

Which was gotten as 1.33 m/s sq

SEE THE ATTACHEMENT FOR DETAILS

8 0
3 years ago
A 170 g air-track glider is attached to a spring. The glider is pushed in 11.2 cm against the spring, then released. A student w
4vir4ik [10]

Answer:k = 10.83 N/m²

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Number of oscillations = 14, time taken = 11s

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By substituting this parameters into ω = √k/m

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7.98 = √k/0.17

By squaring both sides

(7.98)² = k/ 0.17

k = (7.98)² × 0.17

k = 10.83 N/m²

7 0
4 years ago
Which one of the following physical quantities has its S.I. unit m/s?
Rudiy27

Answer:

velocity is the answer of this question.

8 0
3 years ago
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