The vertex of the graph of f(x)= |x-3|+6 is located at (3, 6)
<h3>How to determine the vertex?</h3>
The equation of the function is given as:
f(x) = |x - 3| + 6
The above function is an absolute value function.
An absolute value function is represented as:
f(x) = a|x - h| + k
Where:
Vertex = (h, k)
By comparison, we have:
Vertex = (3, 6)
Hence, the vertex of the graph of f(x)= |x-3|+6 is located at (3, 6)
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Two figure in front
h=16+17 = 33 m
l=18 m
width = 13 m
Volume = lwh = 18*13*33 =7722 m^2
Two figures at the back
h=16 m
l=18+18 =36 m
width = 15 m
Volume = lwh =36*15*16 =8640 m^2
Total volume = 7722+8640 = 16362 m^2
An equation of a circle:
(x - a)² + (y - b)² = r²
(a; b) - a coordinates of a center
r - a radius
r = 8; (-10; 6) ⇒ a = -10 and b = 6
subtitute
(x - (-10))² + (y - 6)² = 8²
Answer: (x + 10)² + (y - 6)² = 64
Y=6x (1)
y=5x-7 (2)
Substitute y into (2)
(6x)=5x-7 -- subtract 5x from both sides
x=-7
Sub x into 1
y=6(-7)
y=-42
x=-7
y=-42
Answer:
40
Step-by-step explanation:
m+25=65
65-25=40
m=40
