Answer:
Please check the explanation.
Explanation:
I carried my logical and administrative skills to stand in implementing the succeeding tasks allocated to me:
- swotting acquiring trends
- investigating client data
- concocting yearly inclination reports.
The bullets and numbering and proper indentation make the reading stuff more easily understandable. And that is what we have done above.
Documents. Note that electronic document is a type of media too.
Answer:
The blocking system.
Explanation:
In order to avoid servers to replicate with each other, I should configure the blocking system of the first DHCP.
For example, if the first DHCP fails to respond, the second will get in place, however, I have to configure the first system that immediately that the second DHCP starts working, the first blocks its information and use.
By this way, there won´t be any duplicated actions or reponses.
Answer:
Following code will store the largest value in array parkingTickets in the variable mostTickets
mostTickets = parkingTickets[0];
for(int k = 0; k<parkingTickets.length; k++)
{
if(parkingTickets[i]>mostTickets)
{
mostTickets = parkingTickets[i];
}
}
Explanation:
In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.
Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.
If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.
This process is repeated for all elements in array.
Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.
