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7nadin3 [17]
3 years ago
12

What is wrong with this code and correct it.

Computers and Technology
1 answer:
balandron [24]3 years ago
8 0

Answer:

What's wrong?

The line_str variable needs to be re-initialized at the end of each printing

The correction

Include the following line immediately after the print statement

       line_str = ""

Explanation:

Required

Correct the code

The conditions are correct. However, the string variable line_str needs to be set to an empty string at the end of every of the iteration loop.

This will allow the code to generate a new string.

So, the complete function is:

<em>def swapping_stars(): </em>

<em>    line_str = "" </em>

<em>    for line in range(0, 6): </em>

<em>        for char in range(0,6): </em>

<em>            if line % 2 == char%2: </em>

<em>                line_str += "*" </em>

<em>            else: </em>

<em>                line_str += "-" </em>

<em>        print(line_str) </em>

<em>        line_str = ""</em>

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Answer:

scanf("%d %lf %c", &age, &pay, &section);

Explanation:

To read the value in c program, the instruction scanf is used.

To read the integer value, use the %d format specifier in the scanf and corresponding variable name age with ampersand operator.

To read the double value, use the %lf format specifier in the scanf and corresponding variable name pay with ampersand operator.

To read the character value, use the %c format specifier in the scanf and corresponding variable name section with ampersand operator.

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3 years ago
Define the term editing​
Harrizon [31]

Answer:

editing is a word file mean making changes in the text contain is a file. or a word file is one of the most basic ms office word operation.

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If you use your computer primarily for telnet into a remote computer, will you have a large long distance telephone bill?
Nikolay [14]

If you use your computer primarily for telnet into a remote computer, a person will not have a large long distance telephone bill.

<h3>What is telnet used for?</h3>

Telnet is known to be a kind of a network protocol that is said to be used to virtually look into a computer and to give a two-way, working hand in hand and text-based communication channel that exist between two machines.

Note that, If you use your computer primarily for telnet into a remote computer, a person will not have a large long distance telephone bill because it does not apply in any way.

Learn more about telnet from

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2 years ago
What kinds of components are tangible assets?
Snezhnost [94]

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Tangible assets are physical like cash, inventory, vehicles, equipment, buildings and investments.

Explanation:

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3 years ago
Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:
horsena [70]

Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed.  So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

          = 0.00833 * 100

          = 0.833 ms

So there is  1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333 / 2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d)  Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0
3 years ago
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