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Lunna [17]
3 years ago
8

Phoebe built the sandbox below for her younger sister.

Mathematics
2 answers:
gogolik [260]3 years ago
5 0
I think its 40ft i hope it helps
Tomtit [17]3 years ago
5 0

Answer: 40 feet

Step-by-step explanation:  Volume = length * width * height

then substitute Volume = 2 * 4 * 5

multiply Volume = 8 * 5

multiply again Volume = 40

hope this helps mark me brainliest if it did have a great day

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I WILL MARK AS BRAINLIEST!!!!
guapka [62]

Answer:

1. 795, 23

2. 50, she will finish her candy on November 21 so she won't be able to share with her cousins

3. $276, 71 cars

Step-by-step explanation:

1. your equation: y = 35x + 235

plug in 16 to find how many pictures she will have on may 16: y = 35(16) + 235

you get y = 795

for the second part, you know are trying to find how long it will take to get to 1024 pictures, so you know your y, but you don't know your x

your equation: 1024 = 35x + 235

solve to get x = 22.54

this rounds up to 23, so your answer is 23

2. multiply 8 times 4 to get 32

subtract 32 from 82 to fin how many she has left

you get 50

for the second part, divide 82 by 4 to find how many day it will take to finish her candy

you get 20.5

so no, she will not have candy to share with her cousins, and she will finish her candy on November 21

3. for this, you have a negative y intercept since you need to make $24 to start profiting

your equation: y = 6x - 24

plug in 50 to x: y = 6(50) - 24

you get y = 276

so you make $276 with 50 cars

for the second part, plug in 400 to y: 400 = 6x - 24

solve to get x = 70.66

this rounds up to 71, so your answer is 71

3 0
3 years ago
The Russo-Japanese War was a conflict between Russia and Japan that started in the year 190419041904. Let xxx represent any year
wel
The first thing we must do for this case is to define a variable.
 We have then:
 x: number of years before the Russo-Japanese conflict began
 We write now the inequality that models the problem.
 We know that the conflict began in the year 1904, therefore, all the previous years are given by:
 x <1904
 Answer:
 
an inequality in terms of x and 1904 that is true only for values of x that represent years before the start of the Russo-Japanese War is:
 
x <1904
4 0
3 years ago
Read 2 more answers
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u &gt; 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
3 years ago
What is 40% of 80 i need help
kotegsom [21]

Answer: = 32

Step-by-step explanation:

40 x 80 / 100 = 32  

4 0
3 years ago
Autumn buys eggs and apples at the store.
soldier1979 [14.2K]

Answer:

\frac{(5.76-34.14)}{6}

Step-by-step explanation:

8 0
2 years ago
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