Question

. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the pressure is 0.750 atm. Assume that the volume remains constant.

Answer 1

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

$\frac{P}{T}=k$

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

$\frac{P1}{T1} =\frac{P2}{T2}$

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

• P1= 0.450 atm
• T1= 20 C= 293.15 K (being 0 C= 273.15 K)
• P2=0.750 atm
• T2= ?

Replacing:

$\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}$

Solving:

$T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }$

$T2=\frac{0.750 atm}{0.450 atm} *293.15K$

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

The final temperature of sulfur dioxide gas is 215.43 C