<span>I believe the correct 2nd reaction is:</span>
cof2(g)⇌1/2 co2(g)+1/2 cf4(g)
where we can see that it is exactly one-half of the
original
Therefore the new Kp is:
new Kp = (old Kp)^(1/2)
new Kp = (2.2 x 10^6)^(1/2)
<span>new Kp = 1,483.24 </span>
Moles of H2SO4= 7.5x10^23/ 6.02x10^23 = 1.25 (3sf) moles of H2SO4
Mass of 1 mole of H2SO4= 98.1g
Therefore mass of 7.5x10^23 molecules of H2SO4= 122.63g
Answer:
uzb-prwk-khj
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