First, put the equation of the line giveninto slope-intercept form by solving fory. You get y = 2x +5, so the slope is –2.Perpendicular lines have opposite-reciprocal slopes, so the slope of theline we want to find is 1/2. answer y=-1/2
Answer:
The odd function is written f (x) = (x) and rounds the odd numbers to the nearest integer.
The graph of f (x) = (x) includes the point (17/4), (7/2), (15/6)
Step-by-step explanation:
The odd function seeks to round odd numbers, with fractions of first odd numbers and then even by adding 3 to them.
Answer:
Step-by-step explanation:
If y varies directly with x, it is:
Constant is -2, it means k= -2
The value of x is ![5\sqrt[3]{25}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B25%7D)
.
Solution:
Given expression is ![-7=8-3 \sqrt[5]{x^{3}}](https://tex.z-dn.net/?f=-7%3D8-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D)
.
Switch both sides.
![8-3 \sqrt[5]{x^{3}}=-7](https://tex.z-dn.net/?f=8-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%3D-7)
Subtract 8 from both side of the equation.
![8-3 \sqrt[5]{x^{3}}-8=-7-8](https://tex.z-dn.net/?f=8-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D-8%3D-7-8)
![-3 \sqrt[5]{x^{3}}=-15](https://tex.z-dn.net/?f=-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%3D-15)
Divide by –3 on both side of the equation.
![$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}](https://tex.z-dn.net/?f=%24%5Cfrac%7B-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%7D%7B-3%7D%20%3D%5Cfrac%7B-15%7D%7B-3%7D)
![\sqrt[5]{x^{3}}=-5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%3D-5)
To cancel the cube root, raise the power 5 on both sides.
![(\sqrt[5]{x^{3}})^5=(-5)^5](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%29%5E5%3D%28-5%29%5E5)
To find the value of x, take square root on both sides.
![\sqrt[3]{x^3}=\sqrt[3]{25}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%3D%5Csqrt%5B3%5D%7B25%7D)
![x=5\sqrt[3]{25}](https://tex.z-dn.net/?f=x%3D5%5Csqrt%5B3%5D%7B25%7D)
Hence the value of x is .
Answer:
a
Step-by-step explanation:
