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Sholpan [36]
3 years ago
12

A/-6 + 8 =12 solve please

Mathematics
2 answers:
posledela3 years ago
6 0

Answer:

A= -24

Step-by-step explanation:

olga55 [171]3 years ago
4 0

Answer:

66

Step-by-step explanation:

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Sybil has 1/2 of a pizza left over. She wants to share the pizza with 3 of her friends. What fraction of the original pizza will
Helen [10]

Answer: \frac{1}{2\times3}=\frac{1}{6}\text{ of the original pizza.}


Step-by-step explanation:

Given: Sybil has 1/2 of a pizza left over.

If she share the pizza with 3 of her friends, to find the fraction of the original pizza will Sybil and her 3 friends each receive, we need to divide 1/2 by 3 we get

The  fraction of the original pizza will Sybil and her 3 friends each receive

=\frac{\frac{1}{2}}{3}=\frac{1}{2\times3}=\frac{1}{6}\text{ of the original pizza.}



6 0
3 years ago
Read 2 more answers
Bethany sells roses and petunias. The expression 3r+2.5p3r+2.5p3, r, plus, 2, point, 5, p gives the cost (in dollars) of rrr ros
Vaselesa [24]

Answer:

I think the equation is written as 3r + 2.5p, where r is the number of roses and p is the number of petunias. To find the total cost, substitute 777 to r and 888 to p. The total cost would then be:

Total Cost = 3r + 2.5p

Total Cost = 3(777) + 2.5(888)

Total Cost = 4551

The total cost would be $4,551.

3 0
3 years ago
Which of these is correct step in constructing congruent angles?
lapo4ka [179]
Is something missing
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6 0
3 years ago
Identify the examples as primary sources or secondary sources.
algol13

Answer:

Primary : letters, artifacts, contracts

Secondary : documentaries, encyclopedias, biographies

Step-by-step explanation:

(I'm not too sure about contracts, so you might want to check yourself for that one)

5 0
3 years ago
There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th
N76 [4]

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

                                                        = 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

                    = 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

                    = 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

3 0
3 years ago
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