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Sholpan [36]
3 years ago
12

A/-6 + 8 =12 solve please

Mathematics
2 answers:
posledela3 years ago
6 0

Answer:

A= -24

Step-by-step explanation:

olga55 [171]3 years ago
4 0

Answer:

66

Step-by-step explanation:

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3 quarts but in cups
Sedaia [141]

Answer:

12 cups

Step-by-step explanation:

there are 4 cups in 1 quart.  You multiply both of them by 3 so there are 12 cups in 3 quarts

8 0
3 years ago
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In the accompanying diagram of parallelogram ABCD,diagonals AC and DB intersect at E, AE = 3x - 4, andEC = x + 12.What is the va
skelet666 [1.2K]

x = 8

Explanation:

AE = 3x - 4

EC = x + 12

SInce diagonals AC and DB intersect at E

it means the lines which meet at the intersection E are equal. A and C meet at E which gives AE and EC

AE = EC

3x - 4 = x + 12

collect like terms:

3x - x = 12 + 4

2x = 16

divide both sides by 2:

2x/2 = 16/2

x = 8

4 0
1 year ago
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad 
C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}
\\\\\\
AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad 
D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}
\\\\\\
BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}
\\\\\\
BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]
\\\\\\
4[15]\implies 60

7 0
3 years ago
Read 2 more answers
The wills tower has a height of 1,451feet.what is the estimated height of the building in meters​
Ivan
Answer: around 442 meters
8 0
3 years ago
5a - 2b -3 + 2b - 6a simplify the expression and then write an equivalent expression. Please anyone help me it's my first questi
svet-max [94.6K]

Step-by-step explanation:

simplify the expression into like terms

so 5a-2b-3+2b-6a (add all a and b together)

this will make

-a-3

I know how to do the equivalent sorry :(

3 0
3 years ago
Read 2 more answers
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