I would most probably say 204
When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
Well 8x25x23 = 4,600 but what do you need to subtract by?
Answer:
The perimeter of the garden is 400 feet.
Step-by-step explanation:
Consider the provided information,
Raja is laying tiles on a path that forms the diagonal of a square garden. If Raja is told that the length of the diagonal path is 
The length of the diagonal of a square garden is 
Let x represent the side of square.
By Pythagorean theorem we know:
Where c is hypotenuse.
The diagonal of the square divides the square into two right angle triangle.
Where, the sides of the square are the legs of the triangle and diagonal is the hypotenuse of the triangle.
Hence, the side of the square is 100 ft.
The perimeter of the square is
where s is the side of square.

Hence, the perimeter of the garden is 400 feet.