Answer:

Explanation:
I assume the volume is 2.50 L. A volume of 25.0 L gives an impossible answer.
We have two conditions:
(1) Mass of glucose + mass of sucrose = 1.10 g
(2) Osmotic pressure of glucose + osmotic pressure of sucrose = 3.78 atm
Let g = mass of glucose
and s = mass of sucrose. Then
g/180.16 = moles of glucose, and
s/342.30 = moles of sucrose. Also,
g/(180.16×2.50) = g/450.4 = molar concentration of glucose. and
s/(342.30×2.50) = s/855.8 = molar concentration of sucrose.
1. Set up the osmotic pressure condition
Π = cRT, so

Now we can write the two simultaneous equations and solve for the masses.
2. Calculate the masses

We have 0.229 g of glucose and 0.871 g of sucrose.
3. Calculate the mass percent of sucrose

1. by making a atomic configuration
2.by making a table of shells of k.l.m.n....
that's all
So, Ba is divalent. This means that each Ba(OH)2 requires two I in order to produce one BaI2 molecule.
The two hydrogens from the 2 HI molecules will combine with 2 OH of Ba(OH)2 forming 2 water (H2O) molecules.
The equation which illustrates this reaction in as follows:
<span>2 HI (aq) + Ba(OH)2 (s) ........> BaI2 (aq) + 2 H2O (l)
</span>where:
aq refers to aqueous state
s refers to solid state and
l refers to liquid state.
Answer:
89.7
Explanation:
First we have to look at the right of the digit which is going to be round. If it is 5 or greater than 5 than the number left to it should be increased by one.
For example
In given number 89.667 after three digits 8, 9, 6 the next digit is 6.
So in order to round the number to three digits 6 will rounded to 7 and value becomes 89.7
If the digit next to rounded digit is less than 5 than number will rounded as,
For example:
56.42
Rounded to three digit it will be 56.4.