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kiruha [24]
3 years ago
7

A very light ping-pong ball moving east at a speed of 4 m/s collides with a very heavy stationary bowling ball. The Ping-Pong ba

ll bounces back to the west, and the bowling ball moves very slowly to the east. Which object experiences the greater magnitude impulse during the collision?A very light ping-pong ball moving east at a speed of 4 m/s collides with a very heavy stationary bowling ball. The Ping-Pong ball bounces back to the west, and the bowling ball moves very slowly to the east. Which object experiences the greater magnitude impulse during the collision?
Physics
1 answer:
KengaRu [80]3 years ago
3 0

Answer:

They experience the same magnitude impulse

Explanation:

We have a ping-pong ball colliding with a stationary bowling ball. According to the law of conservation of momentum, we have that the total momentum before and after the collision must be conserved:

where is the initial momentum of the ping-poll ball

is the initial momentum of the bowling ball (which is zero, since the ball is stationary)

is the final momentum of the ping-poll ball

is the final momentum of the bowling ball

We can re-arrange the equation as follows or

which means (1) so the magnitude of the change in momentum of the ping-pong ball is equal to the magnitude of the change in momentum of the bowling ball.

However, we also know that the magnitude of the impulse on an object is equal to the change of momentum of the object:

(2) therefore, (1)+(2) tells us that the ping-pong ball and the bowling ball experiences the same magnitude impulse:

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A block of mass m slides with a speed vo on a frictionless surface and collides with another mass M which is initially at rest.
Rudik [331]

To solve this problem we will apply the concepts related to the conservation of momentum. Momentum can be defined as the product between mass and velocity. We will depart to facilitate the understanding of the demonstration, considering the initial and final momentum separately, but for conservation, they will be later matched. Thus we will obtain the value of the mass. Our values will be defined as

m_1 = m

m_2 = M

v_{1i} =v_0

v_{2i} = 0

Initial momentum will be

P_i = m_iv_{1i}+m_2v_{2i}

P_i = mv_0

After collision

v_{1f} = v_{2f} = \frac{v_0}{3}

Final momentum

P_f = (m_1+m_2)(\frac{v_0}{3})

P_f = (m+M)(\frac{v_0}{3})

From conservation of momentum

P_f = P_i

Replacing,

(m+M)(\frac{v_0}{3})=mv_0

(m+M)\frac{1}{3} = m

m+M=3m

M=3m-m

M=2m

3 0
3 years ago
Hello!
Montano1993 [528]

It is true that the  light is 15.000 more dangerous than the radiation of a microwave.

<h3>What is the wavelength?</h3>

The wavelength shows the extent or how far the wave travels. Now we know that the energy of the wave can be use to find out how much dangerous the wave is.

Now;

1.6 * 10^-19 J = 1eV

x J = 1.8 eV

x = 1.8 eV * 1.6 * 10^-19 J /1eV

x = 2.88 * 10^-19 J

Now if the energy of the microwaves is 1.2 x 10^-4 J, then it follows that;

2.88 * 10^-19 J/ 1.2 x 10^-4 J,

= 2.4 * 10^15

Hence, it is true that the  light is 15.000 more dangerous than the radiation of a microwave.

Learn more about microwave:brainly.com/question/15708046

#SPJ1

5 0
2 years ago
A 60 N force is applied over a distance of 15 m. How much work was done?
GuDViN [60]

Answer:

900J

Explanation:

w =f×s

60×15

=900J

thus the k.e of the body is 900j

3 0
2 years ago
Describe the steps used by conventional sewage treatment plants to break down our sewage into a relatively safe effluent that ge
anyanavicka [17]

Answer:

the soild material is allowe to settle into a sludge layer the remaining waste water undergoes a secondart treatment that uses bacteria to break down organic matter

treat water is left to sit while particles settle out, with settle d particles being added to sluudge,

water is disinfeted

Explanation:

5 0
3 years ago
Two stones resembling diamonds are suspected of being fakes. To determine if the stones might be real, the mass and volume of ea
dimaraw [331]

Answer:

stone A is diamond.

Explanation:

given,

Volume of the two stone =  0.15 cm³

Mass of stone A = 0.52 g

Mass of stone B = 0.42 g

Density of the diamond =  3.5 g/cm³

So, to find which stone is gold we have to calculate the density of both the stone.

We know,

density\density = \dfrac{mass}{volume}

density of stone A

\rho_A = \dfrac{0.52}{0.15}

\rho_A = 3.467\ g/cm^3

density of stone B.

\rho_B = \dfrac{0.42}{0.15}

\rho_B = 2.8\ g/cm^3

Hence, the density of the stone A is the equal to Diamond then stone A is diamond.

6 0
3 years ago
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