When a suspended string makes and angle of 25 degree while aircraft is accelerating on runway then we can use force equations to find the acceleration of the aircraft

So we will have

$T sin\theta = ma$

$T cos\theta = mg$

now from above two equations we have

$a = g tan\theta$

$a = (9.81) tan25$

$a = 4.57 m/s^2$

now if it took 18 s to take off we can have final speed of the aircraft given by

$v_f - v_i = at$

$v_f - 0 = (4.57)(18)$

$v_f = 82.3 m/s$

6 0

3 years ago

Final velocity for 2.6 seconds

enyata [817]

That's going to depend on the initial velocity, and how it changes
or doesn't change during the 2.6 seconds. I've read the question,
and Im pretty sure you didn't tell us any of that.

3 0

4 years ago

Which of the following best describes a consumer?

Stella [2.4K]

Answer:

a business who buys goods and services

7 0

4 years ago