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Lana71 [14]
3 years ago
11

The three osicles known as the hammer, anvil and stirrup __________.

Physics
1 answer:
34kurt3 years ago
3 0
Malleus, incus, and stapes, respectively, and collectively, as "middle ear ossicles<span>".</span>
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A6 cm object is 8 cm from a convex lens that has a focal length of 2.7 cm. The image is 4 cm from the lens. The height of the im
Marrrta [24]

Answer:

7.8cm

Explanation:

5 0
2 years ago
Read 2 more answers
A small metal cube measures 2.5 cm on one side. The mass of the cube is 1129.56 g. What is the density of the cube?
attashe74 [19]

-- volume = (length)(width)(height)

-- Since the cube is a cube, its three dimensions are all the same number.

Volume = (2.5cm)(2.5cm)(2.5cm)

Volume = 15.625 cubic cm

-- density = (mass) / (volume)

Density = (1129.56g) / (15.625cm^3)

Density = 72.3 g/cm^3

(roughly 3.2 TIMES the density of the most dense naturally occurring substance on Earth)

8 0
3 years ago
An ice cube at 0c was dropped into 30.0 g of water in a cup at 45.0c. at the instant that all of the ice was melted, the tempera
Ede4ka [16]
The amount of heat given by the water to the block of ice can be calculated by using
Q=m_w C_{sw} \Delta T_w
where 
m_w = 30 g is the mass of the water
C_{sw}=4.18 J/(g ^{\circ}C) is the specific heat capacity of water
\Delta T_w = 45.0^{\circ}-19.5^{\circ}C = 20.5^{\circ}C is the variation of temperature of the water.

Using these numbers, we find
Q=(30 g)(4.18 J/(g^{\circ}C))(20.5^{\circ}C)=2571 J

This is the amount of heat released by the water, but this is exactly equal to the amount of heat absorbed by the ice, used to melt it into water according to the formula:
Q = m_i L_f
where m_i is the mass of the ice while L_f =334 J/g is the specific latent heat of fusion of the ice.
Re-arranging this formula and using the heat Q that we found previously, we can calculate the mass of the ice:
m_i =  \frac{Q}{L_f}= \frac{2571 J}{334 J/g} =7.7 g
3 0
2 years ago
Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p
Marta_Voda [28]

Answer:

Acceleration, a=9.91\times 10^{15}\ m/s^2

Explanation:

It is given that,

Separation between the protons, r=3.73\ nm=3.73\times 10^{-9}\ m

Charge on protons, q=1.6\times 10^{-19}\ C

Mass of protons, m=1.67\times 10^{-27}\ kg

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

ma=\dfrac{kq^2}{r^2}

a=\dfrac{kq^2}{mr^2}      

a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}      

a=9.91\times 10^{15}\ m/s^2

So, the acceleration of two isolated protons is 9.91\times 10^{15}\ m/s^2. Hence, this is the required solution.

3 0
3 years ago
On a 10 kg cart (shown below), the cart is brought up to speed with 50N of force for 7m, horizontally. At this point (A), the ca
pav-90 [236]
Answer: Letter B! Is your answer
3 0
2 years ago
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