Specific heat formula is Q=M*C*ΔT
Q is amount of energy (4786 J)
M is mass (89.0 g)
C is specific heat (unknown, answer will be in J/gºC)
ΔT is the change in temp (89.5-23.0=66.5ºC)
Let's plug it in.
4786=89.0(C)(66.5)
4786=5918.5(C)
/5918.5
C=.8086508406 J/gºC
with sig figs...
C=.809 J/gºC
Your answer would be C as it’s not part of the reproductive system.
Answer:
P = ![P_{atm} + \rho \ g \ h](https://tex.z-dn.net/?f=P_%7Batm%7D%20%2B%20%5Crho%20%5C%20g%20%5C%20h)
Explanation:
For this exercise we use that the pressure at a given level is the same, so we set a level on both sides of the pressure gauge, just the point where the liquid is on the system side, with a pressure (P)
P =
where
is the atmospheric pressure in pascals, ρ the density of the liquid, g is related to gravity and h the height of the liquid from the marked reference.
Virtual images are produced when rays of a light (after reflection or refraction) appear to meet a a certain point. While real images are produced when rays of a light (after reflection or refraction) meet at some point.
Answer:
Forms over water, warm humid air mass, it's a polar air mass
Explanation: I think that's right sorry if it's not..
GL! :)