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Nookie1986 [14]
3 years ago
6

Find two consecutive odd integers such that three times the larger is 5 less than four times the smaller

Mathematics
1 answer:
S_A_V [24]3 years ago
3 0
Let n=smallest number
Let n+2=largest number

3(n+2)=4(n)-5
3n+6=4n-5
-n=-11
n=11

11+2=13

The smallest number is 11 and the largest number is 13
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