A system of linear equations has been graphed in the diagram. Determine a reasonable solution for the system of equations.
2 answers:
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Answer: No, he can't pass the course.
Explanation:
Since we have given that
Marks on tests 1, 2, and 4 are given by
82, 76, 90 respectively.
Unfortunately, he cut the third test and receive a 0.
According to question, we have given that passing grade for the course is 70, and his one test left to take ,
Let the marks obtained in fifth test be x
So,
And it is not possible to get 102 over 100.
so, he can't still pass the course.
Hence, No, he can't pass the course.
Principal, P = $500
r =8% = 0.08, the interest rate
n = 1, the compounding interval
t = 6 years
The value after 6 years is
That is,
A = $500*(1 + 0.08)⁶ = $793.44
Answer: $793.44
r =8% = 0.08, the interest rate
n = 1, the compounding interval
t = 6 years
The value after 6 years is
That is,
A = $500*(1 + 0.08)⁶ = $793.44
Answer: $793.44