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mars1129 [50]
3 years ago
6

Increase 19060 by 9%

Mathematics
1 answer:
babunello [35]3 years ago
6 0

Answer:

0.05

Step-by-step explanation:

brainliest plz

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(-4, 2) and (3, -3)?
Gnom [1K]

Answer:

m=-\frac{5}{7}; see graph.

Step-by-step explanation:

Using the slope formula:

m=\frac{rise}{run}=\frac{-3-2}{3+4}=\frac{-5}{7}=-\frac{5}{7}

6 0
3 years ago
F (x) = (x - 6)2(x + 2)2
riadik2000 [5.3K]

Answer:

Step-by-step explanaf(x) = (x^{2} - 6x + 36) . (x^{2} + 2x + 4)\\f (x) = (x^{4} + 2x^{3}  + 4x^{2} - 6x^{3} - 12x^{2} - 24x + 36x^{2} + 72x + 144)\\f(x) = (x^{4} - 4x^{3} + 28x^{2} + 48x + 144)

7 0
3 years ago
The exterior angles of a quadrilateral measure 3x + 10, 2x - 60, 3x + 23, and 2x - 13. Find the measure of each angle.
Marat540 [252]
3x + 10 + 2x -60 + 3x +23 +2x - 13 = 360
10x -40 = 360
10x - 40 +40 = 360 +40
10x = 400
10x/10 = 400/10
x = 40

3x+10 = 3(40)+10 = 130°
2X-60 = 2(40) -60 = 20°
3X+23 = 3(40)+23 = 143°
2x-13 = 2(40)-13 = 67°

6 0
4 years ago
Read 2 more answers
Write an exponential function in the form y=ab^x that goes through points (0,7) and<br> (9, 3584).
erastovalidia [21]

Answer:y=7(2)^x

Step-by-step explanation:

6 0
3 years ago
A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modele
aev [14]

THIS IS THE COMPLETE QUESTION

basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball reaches the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?

Yes, exactly 0.6 seconds after the shot is launched.

Yes, between 0.64 seconds and 0.65 seconds after the shot is launched

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

No, the shot is not blocked.

Answer:

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Given that the

equation for shot block height h = 9 + 25t – 16t2.

equation for ball height h = 6 + 30t – 16t2.

From the question ,it can be deducted that the shot is made before two tenths of a second or 0.2seconds

CHECK THE ATTACHMENT TO COMPLETE THE DETAILED SOLUTION

5 0
3 years ago
Read 2 more answers
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