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Temka [501]
3 years ago
12

Solve the equation below. SHOW ALL WORK! 5(x − 2) = 40

Mathematics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

Ans is downward

Step-by-step explanation:

Hope it helps u

plz mark as brainlist

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Step-by-step explanation:

8 0
3 years ago
Which point is on the graph of f(x) =5x?
Lena [83]

Answer:

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5*10

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8 0
3 years ago
Draw the image of △ABC under a dilation whose center is P and scale factor is 1/2
Vesna [10]

Answer:

Step-by-step explanation:

Let the point P is at the origin (0, 0).

Then the coordinates of A, B and C will be (8, 4), (-2, 2) and (4, -4) respectively.

Rule for the dilation of a point by a scale factor = k

(x, y) → (kx, ky)

If k = \frac{1}{2}

Then, A(8, 4) → A'(4, 2)

          B(-2, 2) → B'(-1, 1)

         C(4, -4) → C'(2, -2)

Now we can plot the new image with points A', B' and C'

3 0
3 years ago
Prove that x 2 + y2 - 1 is irreducible in q[ x, y].
weqwewe [10]
Suppose that the polynomial x^2+y^2-1 is not irreducible. 
It means that there exists two fractions such that :
(\frac{p}{q})^2+( \frac{s}{t} )^2 -1=0\\\text{rearranging the above formula we get:}\\p^2t^2=q^2(t^2-s^2)\\\text{since q and p are primes each other, we deduce that }\\\text{q divide t meaning that we can write }t=a\times t\text{ for an integer a}\\\text{rearranging again the formula and using our finding we get:}\\q^2s^2=a^2q^2(q^2-p^2)\\\text{Same argument as above, we deduce that q divide s.}
We found that q divide t and q divide s, but s and t are supposed to be prime each other. It is a contradiction. 
The polynomial x^2+y^2-1 is then irreducible in q[x,y] 
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4 years ago
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Hope this helps with the answer :)

8 0
3 years ago
Read 2 more answers
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