Answer:
.009 miles/hour
Step-by-step explanation:
![\frac{7.5}{10}\frac{feet}{minutes} * \frac{1}{5280} \frac{miles}{feet} *\frac{60}{1}\frac{minutes}{hour}](https://tex.z-dn.net/?f=%5Cfrac%7B7.5%7D%7B10%7D%5Cfrac%7Bfeet%7D%7Bminutes%7D%20%2A%20%5Cfrac%7B1%7D%7B5280%7D%20%20%20%5Cfrac%7Bmiles%7D%7Bfeet%7D%20%2A%5Cfrac%7B60%7D%7B1%7D%5Cfrac%7Bminutes%7D%7Bhour%7D)
This is the method you should take with unit conversions in general, just set up fractions so the units cancel out, like the 7.5 feet cancels out with the feet in the 1/5280 so miles is left on top.
2y+4=3(y-1)
2y+4=3y-3
4+3=3y-2y
Y=7
X=2
I believe if that says three minus four times three minus five or three plus negative four times three plus negative five (same thing) then the answers should be positive two (2.)
Answer:
We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Step-by-step explanation:
We know that the perimeter of a rectangle = 2(l+w)
i.e.
P = 2(l+w)
Here
Given that the length and width of the playground by a scale factor of 2
A scale factor of 2 means we need to multiply both length and width by 2.
i.e
P = 2× 2(l+w)
P' = 2 (2(l+w))
= 2P ∵ P = 2(l+w)
Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.